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3 years ago

For which of the following can the composition vary?

Chemistry

2 answers:

Mice21 [21]3 years ago

6 0

Answer:

Option a. both homogeneous and heterogeneous mixture.

Explanation:

This can be explained as a mixture is the combination of more than one substances mixed together while retaining their identities or chemical properties.

Homogeneous mixtures in which the components are mixed in the same amounts or proportion, i.e., it has uniformity in it.

Heterogeneous mixtures in which the constituents are not mixed in uniform proportion and are separable.
Pure elements are those which have the a stable isotope or the atomic number of which are same.
Thus the composition can only vary in homogeneous and heterogeneous mixtures.

Margarita [4]3 years ago

5 0

Answer: Option (a) is the correct answer.

Explanation:

A homogeneous mixture is defined as a mixture that contains evenly distributed solute particles into the solvent.

For example, NaCl dissolved in water is a homogeneous solution.

On the other hand, a solution in which solute particles are not evenly distributed into the solvent is known as a heterogeneous mixture.

For example, when sand is added to water then it forms a heterogeneous solution.

Thus, we can conclude that for both homogeneous and heterogeneous mixtures the composition vary.

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General Chemistry fourth edition by McQuarrie, Rock, and Gallogly. University Science Books presented by Macmillan Learning.

Helen [10]

Answer:

3.07 Cal/g

Explanation:

Step 1: Calculate the heat absorbed by the calorimeter

We will use the following expression.

Q = C × ΔT

where,

Q: heat absorbed

C: heat capacity of the calorimeter (37.60 kJ/K = 37.60 kJ/°C)

ΔT: temperature change (2.29 °C)

Q = 37.60 kJ/°C × 2.29 °C = 86.1 kJ

According to the law of conservation of energy, the heat released by the candy has the same magnitude as the heat absorbed by the calorimeter.

Step 2: Convert 86.1 kJ to Cal

We will use the conversion factor 1 Cal = 4.186 kJ.

86.1 kJ × 1 Cal/4.186 kJ = 20.6 Cal

Step 3: Calculate the number of Cal per gram of candy

20.6 Cal/6.70 g = 3.07 Cal/g

3 0

2 years ago

The reaction of 5.40 g of carbon with excess O2 yields 13.6 g of CO2. What is the percent yield of this reaction?

vazorg [7]

C + O2= CO2
$n = \frac{m}{mw}$
$n = \frac{5.4}{12} \\ n = 0.45 \: mol \: of \: carbon$
$n = \frac{13.6}{12 + 16 \times 2} \\ n = \frac{13.6}{44} \\ n = 0.31 \: mol \: of \: carbon \: dioxide$
CO2 is limit
5.4-3.72= 1.68 g of C is excess
5.4 g = 100%
3.72 g = x
x=68.9 %

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2 years ago

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e-lub [12.9K]

The answer is A: accuracy

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1 year ago

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Artyom0805 [142]

look good w small changes below:

Answer:

AB is an ionic compound. The electronegativity difference between A and B is greater.

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2 years ago

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• Describe how ultrasound and infrasound are used in specific industrial applications and provide detailed examples.

xeze [42]

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