2 ( 4 x + 4 ) + 6 ( 2 x + 6 ) + 4 = 20 x + 48 solving for x
1 answer:
You might be interested in
Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=
x=
x=
x=
x=
there are no real numbers that satisfy this
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=
x=
x=
x=
x=
there are no real numbers that satisfy this