Answer:
PLEASE SHOW THE FIGURE PLEASE SO THAT I CAN HELP YOU
Answer:
See the graph attached. It has one solution: (6,-4)
Step-by-step explanation:
The slope-intercept form of a line is:
Where m is the slope and b is the intersection of the line with the y-axis.
Given the first equation
You can identify that:
b=-1
Substitute y=0 to find the intersection with the x-axis
This line passes through the points (0,-1) and (-2,0)
Given the second equation:
Solve for y:
It passes through the point (0,-4).
Now, you can graph. See the figure attached.
It has one solution,which is the point of intersection of both lines: (6,-4)
Answer: he has 128 + d
Step-by-step explanation:
well if he had 128 yesterday and today he got d more just add d to 128 and ull see
for example, lets say d = 16
to find out the total we woukd have to add 16 to 128 (just an example the answer is not d=16)
answer= 128+d
Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.