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Anuta_ua [19.1K]
3 years ago
14

How do you perform this: 2x+3y=25 3x+4y=22

Mathematics
1 answer:
meriva3 years ago
6 0

Answer:

x = -34 , y = 31

Step-by-step explanation suing Gaussian elimination:

Solve the following system:

{2 x + 3 y = 25

3 x + 4 y = 22

Express the system in matrix form:

(2 | 3

3 | 4)(x

y) = (25

22)

Write the system in augmented matrix form and use Gaussian elimination:

(2 | 3 | 25

3 | 4 | 22)

Swap row 1 with row 2:

(3 | 4 | 22

2 | 3 | 25)

Subtract 2/3 × (row 1) from row 2:

(3 | 4 | 22

0 | 1/3 | 31/3)

Multiply row 2 by 3:

(3 | 4 | 22

0 | 1 | 31)

Subtract 4 × (row 2) from row 1:

(3 | 0 | -102

0 | 1 | 31)

Divide row 1 by 3:

(1 | 0 | -34

0 | 1 | 31)

Collect results:

Answer: {x = -34 , y = 31

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Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.
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Answer:

Equation of the line that passes through the given point and is (a) parallel is: \mathbf{y=-2x+11}

Equation of the line that passes through the given point and is (b) perpendicular is: \mathbf{y=\frac{1}{2}x+1}

Step-by-step explanation:

We need to Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.

First we will find slope of the line given in graph

The slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have points (1,6) and (2,2)

Slope is:

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{2-6}{2-1}\\Slope=\frac{-4}{2}\\Slope=-2

Part a)

Write an equation of the line that passes through the given point and is (a) parallel

When the lines are parallel, they have same slope. So, slope of required line: m = -2

Using slope m =-2 and point(4,3) we can find y-intercept b

y=mx+b\\3=-2(4)+b\\3=-8+b\\b=3+8\\b=11

The equation of line will be:

y=mx+b\\y=-2x+11

Equation of the line that passes through the given point and is (a) parallel is: \mathbf{y=-2x+11}

Part b)

Write an equation of the line that passes through the given point and is (b) perpendicular

When the lines are perpendicular they have opposite slope. So, slope of required line: m = 1/2

Using slope m =1/2 and point(4,3) we can find y-intercept b

y=mx+b\\3=\frac{1}{2}(4)+b\\3=2+b\\b=3-2\\b=1

The equation of line will be:

y=mx+b\\y=\frac{1}{2}x+1

Equation of the line that passes through the given point and is (b) perpendicular is: \mathbf{y=\frac{1}{2}x+1}

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