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3 years ago

14

Paul has just enough money to buy either 5 erasers and 30 pencils or 10 erasers and 24 pencils. Each eraser costs $0.30. How muc

h does each pencil cost?

1 answer:

jasenka [17]3 years ago

6 0

Each pencil will cost $0.25

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Please answer this as soon as possible

skelet666 [1.2K]

Answer:x=-8

Step-by-step explanation:

12(x/4+2/3)=12(x/6)

3x+8=2x

3x-2x=-8

x=-8

3 0

3 years ago

Read 2 more answers

What's 5 divided by 3 1/3?

Dafna11 [192]

Answer: 3/2

Step-by-step explanation:

We can start by converting 3 1/3 to an improper fraction. Since 3 is equal to 9/3, 3 1/3 would be equal to 9/3 + 1/3 = 10/3.

Therefore, we are doing $\frac{5}{\frac{10}{3}}$ .

Dividing 5 by 10/3 is the same as multiplying 5 and the reciprocal of 10/3, which is 3/10.

5*3/10 = 15/10 = 3/2.

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2 years ago

What is 3.75 multiplied 2.6

Ivanshal [37]

Answer:

The answer to that is 9.75

Step-by-step explanation:

Hope this helps! Good luck

8 0

3 years ago

Read 2 more answers

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$

3 0

3 years ago

10. There are 355 students at Median Middle School. If there 8% of the students were absent on Tuesday, how many students were a

Setler79 [48]

To solve this question, we simply need to divide the total amount of students by 8% to find out how many students were absent and how many were present.

However, we can't simply multiply it by 8%, so we need to turn that into a decimal.

8% - 0.08

<em>Multiply:</em>

<em>355 x 0.08</em>

<em>= 28.4</em>

<em>Round:</em>

<em>28 kids were absent</em>

<em>Subtract:</em>

<em>355 - 28</em>

<em>= 327</em>

<em />

<em>This means that </em><em>28 kids were absent</em><em>, and </em><em>327 kids were present</em><em>.</em><em> </em>

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6 0

2 years ago