Answer:
a) 46.98%
b) increasing rate of change
Step-by-step explanation:
In year 1987, investment worth $29800
In year 1997, investment worth $43800
Rate of change = 1997investment - 1987investment / 1987investment × 100
Rate of change = 43800 - 29800/29800 × 100
= 14000/29800 × 100
= 0.46979 × 100
= 46.98%
Therefore, the rate of change of the investment during the time period is 46.98%.
b) The rate of change of the investment is increasing. This is as a result of the following reasons. First, the value of rate of change is positive. Second, there is no value for rate of change for period before the time period so we cannot compare rate of change.
Good luck to Jonathan. I hope he gets his sport set soon.
Hopefully I drew what you described.
The 6.6 represents the total of N + 3.4
We subtract the part we know from the whole /sum/total we know to get the other part.
So 6.6 - 3.4 = N
3.2 = N
Answer:
(-4, -3)
Step-by-step explanation:
The graph of both lines will be shown below.
To find the solution, we need to find the point on the graph that both lines intersect on.
As we can see, both lines intersect on the point (-4, -3). Thus, that is the solution.
Best of Luck!