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2 years ago

Can some please help me with this problem It's a little confusing to me.

Mathematics

2 answers:

Nat2105 [25]2 years ago

4 0

Diameter = 10.0002 inches, or 10 inches since were rounding to the nearest whole number.

Kamila [148]2 years ago

4 0

Answer:

need points sorry

Step-by-step explanation:

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Pls help asap or else my parents will kill me eeeeeasy and explian for brainleest .

gtnhenbr [62]

Answer:

Step-by-step explanation:

I'm assuming that your "70=50x what is xx" actually means "find x if 70-50x = 0" If that's not what you meant, please retype your question.

Dividing both sides by -50 results in -70/50 + x = 0, and adding 70/50 to both sides results in x = 70/50, or 7/5.

Only if my assumptions are correct: x = 7/5.

3 0

2 years ago

The length of a rectangle is three times its width the length is 3 3/4 feet. What is the area if the rectangle?

Roman55 [17]

Answer:

A = 4 11/16 or 4.6875

Step-by-step explanation:

3 3/4 = 3W

divide both sides by 3

15/4 divided by 3 = W

15/4 x 1/3 = W

5/4 = W

A = L x W

3 3/4 x 1 1/4 = 15/4 x 5/4 = 75/16 = 4 11/16

4 0

2 years ago

4. Are the lines parallel, perpendicular, or neither?

Lelu [443]

Answer:

Perpendicular

Step-by-step explanation:

Intersect over each other

4 0

3 years ago

Combining like terms with negative coefficients & distribution

Leno4ka [110]

$- 4(z + 3) - 4(5 - 4z) \\ = - 4z - 12 - 20 + 16z \\ = 12z - 32$

6 0

3 years ago

7- a. What is the radius of the circle with center (3,10) that passes through (12,12)?

loris [4]

Answer: a. Radius of circle = $\sqrt{85}$

b. The equation of this circle : $(x-3)^2+(y-10)^2=85$

Step-by-step explanation:

Given : Center of the circle = (3,10)

Circle is passing through (12,12).

a. To find the radius we apply distance formula (∵ Radius is the distance from center to any point ion the circle.)

Radius of circle = $\sqrt{(12-3)^2+(12-10)^2}$

Radius of circle = $\sqrt{(9)^2+(2)^2}=\sqrt{81+4}=\sqrt{85}$

i.e. Radius of circle = $\sqrt{85}$

b. Equation of a circle = $(x-h)^2+(y-k)^2=r^2$ , where (h,k)=Center and r=radius of the circle.

Put the values of (h,k)= (3,10) and r= $\sqrt{85}$ , we get

$(x-3)^2+(y-10)^2=(\sqrt{85})^2$

$(x-3)^2+(y-10)^2=85$

∴ The equation of this circle : $(x-3)^2+(y-10)^2=85$

6 0

3 years ago