1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnesinka [82]
2 years ago
6

Help me plz due tommarow

Mathematics
1 answer:
solong [7]2 years ago
6 0
Make a proportion the sales tax is a percent of the total purchase and you just have to figure that out. 1,200/100=72/x solving this i get 6% sales tax using that. I find the rest by taking 6% of 2500 =150. And for part b make another proprtion x/100=108/6. And i get 1800 dollars
You might be interested in
The graph shows the amount of money earned by two different workers.
Masteriza [31]

Answer:

The asnwer is B

Step-by-step explanation:

HOPE YOU DO WELL

3 0
3 years ago
Read 2 more answers
What is 3.96 × 0.4, please help me ​
Kisachek [45]

Answer:

1.584

Step-by-step explanation:

1.584 = 3.96 × 0.4

8 0
3 years ago
Read 2 more answers
Suppose brine containing 0.2 kg of salt per liter runs into a tank initially filled with 500 L of water containing 5 kg of salt.
Oliga [24]

Answer:

(a) 0.288 kg/liter

(b) 0.061408 kg/liter

Step-by-step explanation:

(a) The mass of salt entering the tank per minute, x = 0.2 kg/L × 5 L/minute = 1 kg/minute

The mass of salt exiting the tank per minute = 5 × (5 + x)/500

The increase per minute, Δ/dt, in the mass of salt in the tank is given as follows;

Δ/dt = x - 5 × (5 + x)/500

The increase, in mass, Δ, after an increase in time, dt, is therefore;

Δ = (x - 5 × (5 + x)/500)·dt

Integrating with a graphing calculator, with limits 0, 10, gives;

Δ = (99·x - 5)/10

Substituting x = 1 gives

(99 × 1 - 5)/10 = 9.4 kg

The concentration of the salt and water in the tank after 10 minutes = (Initial mass of salt in the tank + Increase in the mass of the salt in the tank)/(Volume of the tank)

∴ The concentration of the salt and water in the tank after 10 minutes =  (5 + 9.4)/500 = (14.4)/500 = 0.288

The concentration of the salt and water in the tank after 10 minutes = 0.288 kg/liter

(b) With the added leak, we now have;

Δ/dt = x - 6 × (14.4 + x)/500

Δ = x - 6 × (14.4 + x)/500·dt

Integrating with a graphing calculator, with limits 0, 20, gives;

Δ = 19.76·x -3.456 = 16.304

Where x = 1

The increase in mass after an increase in = 16.304 kg

The total mass = 16.304 + 14.4 = 30.704 kg

The concentration of the salt in the tank then becomes;

Concentration = 30.704/500 = 0.061408 kg/liter.

6 0
3 years ago
Simplify the expression by combining like terms put each expression in its simplest form. 1. 5x^2-2xy+3y^2-4yx+3x-4y^2-5xy+2x-y
Reptile [31]
5x^2-7xy-2y^2-4yx+3x+2x
3 0
2 years ago
Read 2 more answers
Find the value of c. 64 32 5c+2 C​
Dmitry [639]

Answer:

c = 6

Step-by-step explanation:

(I'm going to call the unidentified inner angle Henry, 'kay?)

First, we need to find Henry.

64 + Henry = 180

(64 - 64) + Henry = (180 - 64)

Henry = 116

Now to c.

Henry + 32 + 5c + 2 = 180

(116 + 32 + 2) + 5c = 180

(150 - 150) + 5c = (180 - 150)

5c/5 = 30/5

c = 6

5 0
3 years ago
Other questions:
  • These dot plots show the heights (in feet) from a sample of two different
    5·1 answer
  • 2+1/6w=-4 What would be the anwsers? you need to solve, what is w
    12·1 answer
  • A student model the relationship in the table with the equation x = 4y. Explain the student's error. Write and equation that cor
    15·1 answer
  • BRAINLY!! 20 POINTS!!
    6·2 answers
  • -√5 is a real number​
    11·1 answer
  • Help help i need help please​
    15·1 answer
  • If a window is 10 in + 14 in + 4 in what is the area of the window
    6·1 answer
  • Graph the line with the equation y= 2/5x+3 ?<br><br> ​
    7·1 answer
  • Need help with some math
    10·1 answer
  • Generate a frequency table for the following data: 3, 12, 25, 2, 3, 6, 17, 17, 15, 13, 20, 12, 21, 18, 19.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!