A median is 65 inches and a standard deviation is 1.7:
a. 65 + 1 SD = 65 + 1.7 = 66.7 in
It means that there are : 100% - ( 50% + 34% ) = 100% - 84% = 16% students taller than 66.7 inches.
b. Heights between 61.6 in and 68.7 in are within 2 standard deviations:
13.5% + 34% + 13.5% + 34% = 95%
0.95 * 300 = 285
There are 285 students between 61.6 in and 68.7 in tall.
The vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)
<h3>How to determine the new vertices?</h3>
The vertices are given as:
a (-6,-7)
b(-3,-10)
c(-5,2)
The transition rule is given as
(x,y)-->(x,y-3)
So, we have
a' = (-6, -7 - 3)
a' = (-6, -10)
b' = (-3, -10 - 3)
b' = (-3, -13)
c' = (-5, 2 - 3)
c' = (-5, -1)
Hence, the vertices of abc given the transition rule (x,y)-->(x,y-3) are (-6, -10), (-3, -13) and (-5, -1)
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D.8+d=43 because two negatives do make a positive in mathmatics
