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emmasim [6.3K]
3 years ago
10

The endpoints of a line segment are G(1,7) and H(-3,11). Find the coordinates of the midpoint M.

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0

Answer:

The answer is

<h2>( 1 , 9)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

G(1,7) and H(-3,11)

The midpoint is

M  = ( \frac{ - 1 + 3}{2} , \:  \frac{7 + 11}{2} ) \\  = ( \frac{2}{2}  \:  , \:  \frac{18}{2} )

We have the final answer as

<h3>( 1 , 9)</h3>

Hope this helps you

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The expression which is equivalent to the given expression as in the task content is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.

<h3>What is the expression which is equivalent to the given expression?</h3>

According to the task content, it follows that the expression given is;

(1.5⁵/0.7⁴)³

= 1.5^(3×5) /0.7^(4×3)

= 1.5¹⁵/0.7¹².

Hence, the expression which is equivalent is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.

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brainly.com/question/847241

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Answer:

a) P [ Z > 70 ]  = 0.1075  or 10.75 %

b)  P [ Z < 60 ] = 0.1038   or  10.38 %

c)  P [ 55 ≤ Z ≤ 70 ] =  0.8882   or 88.82 %

Step-by-step explanation:

Normal Distribution  μ = 65    and σ = 4

a) The probability of the car travels more than 70 miles per gallon is:

P [ Z > 70 ]  =  (Z-μ) ÷ σ  ⇒   P [ Z > 70 ] = (70-65) ÷4     P [ Z > 70 ] = 1.25

the point 1.25 corresponds at values, from left tail up to 70 so we must go and look for the area for the point 1.24 which is 0.8925. Then we have the area or probability of all cars traveling up  to 70 miles therefore  we have to subtract 1 -0,8925

P [ Z > 70 ]  = 0.1075  or 10.75 %

b)The probability of the car travels less than 60 miles per gallon is:

P [ Z < 60 ]  = ( 60 - μ ) ÷  σ ⇒  P [ Z < 60 ] = (60-65)÷ 4    P [ Z < 60 ] = -1.25

Again -1.25 corresponds to 60 miles per gallon threfore we move to the left and find for point -1.26  which area is 0.1038 so

P [ Z < 60 ] = 0.1038     10.38 %

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For  point  Z = 70 or 1.25 (case a above)  P [ Z ≤ 70] = (70-65)÷4  

P [ Z ≤ 70] = 1.25

In this case we got the whole area from the left tail up to 1.25

P [ Z ≤ 70]  = 0.8944 (includes the area of the point from the left tail up to the point assocciated to 55 miles and for that reason we have to subtract that area)

P [ Z ≥ 55 ]  = (55-65) ÷ 4     P [ Z ≥ 55 ] = -2.5  and the area is 0.0062

So P [ 55 ≤ Z ≤ 70 ] =  0.8944 - 0.0062  = 0.8882

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Answer:

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Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

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