Answer:
FALSE
Explanation:
Because C1 and C2 implement the same interface, they both implement whichIsIt. The variable c is known as a polymorphic variable, meaning that it can change from being an C1 to a C2. So, the message c.whichIsIt( ); may invoke C1's whichIsIt or C2's whichIsIt. This can only be known at runtime.
Answer:
The answer is letter C.
Explanation:
He uses the old phone, cabled to an existing telephone port, and not to any new device.
