Answer:
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Answer:
START LOOP FOR EACH EMPLOYEE:
INPUT employee’s name, hourly rate of pay, number of hours worked, overtime pay rate, payroll deductions, tax rate
SET gross pay = (hourly rate of pay x *weekly hours) + (overtime pay rate x (number of hours worked - *weekly hours))
PRINT gross pay
SET net pay = gross pay - (payroll deductions + (gross pay * tax rate/100 ))
PRINT net pay
END LOOP
* weekly hours (how many hours an employee needs to work to earn overtime pay rate) is not given in the question
Explanation:
Create a loop that iterates for each employee
Inside the loop, ask for name, hourly rate, number of hours worked, overtime pay rate, payroll deductions, tax rate. Calculate the gross pay and print it. Calculate the net pay and print it
Answer:
phones = {'John': '1234567', 'Julie' : '7777777'}
Explanation:
In the code given in the question phones dictionary contains contains two keys John and Julie and have the values '5555555' and '7777777' respectively. Now in the code the key John in the dictionary phones is assigned the value '1234567' .So the value corresponding to the key John becomes '1234567'.
Answer:
Follows are the method definition to this question:
void Reverse_Order(struct Node* h)//defining a recursive method Reverse_Order that takes structure in parameter
{
if (h == NULL)//use if block to check head equal to null
return;//use return keyword
Reverse_Order(h->next);//call method recursively
cout<<h->data;//print data
}
Explanation:
In the above code, a recursive method "Reverse_Order" takes structure as the parameter, and inside the method, structure variable h is used that uses the if conditional statement to check the header equal to null.
In the condition is true, it will use the return keyword, and in the next step, it calls the method recursively, and print its value in the reverse order.
