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kirza4 [7]
3 years ago
9

Catherine studied 1.25 hours for her science test. This was 0.5 hours less than she studied for her algebra test. Write and solv

e a subtraction equation to find how long she studied for her algebra test.
Mathematics
2 answers:
masha68 [24]3 years ago
7 0
The equation would be: 1.25hours + 0.5hours
When solved, Catherine would have studied for her Algebra test for 1.75 hours.
Mandarinka [93]3 years ago
3 0
The answer would be 45 minutes
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21 points!!
exis [7]

Answer:

Simple multiplication gets you 124

Step-by-step explanation:

9x13=117

117+7=124

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9 reps bags, 13 reps cookies, 7 reps cookies already had.

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Cloud [144]

Answer:

9.42

Step-by-step explanation:

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What is the value of (4xy)^0
VMariaS [17]
Its1.  every number/variable that has a power to the zero, its goin to turn out to be just one
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3 years ago
The diagonals of a rhombus are 21 m and 32 m. What is the area of the rhombus?<br> 30 POINTS
Wittaler [7]
I have included attachment below

so since a rhombus is 2 pairs of paralell sides, we can cut it into 4 triangles
we can see that we can take the bottom 2 triangles and put them on top to get a rectangle that is width 21 and height 32/2 (16=height
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5 0
3 years ago
In a NiCd battery, a fully charged cell is composed of Nickelic Hydroxide. Nickel is an element that has multiple oxidation stat
Westkost [7]

Answer:

P(cell has at least one of the positive nickel-charged options) = 0.83.

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.

Step-by-step explanation:

It is given that the Nickel Charge Proportions found  in the battery are:

0 ==> 0.17

.

+2 ==> 0.35

.

+3 ==> 0.33

.

+4 ==> 0.15.

The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.

a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.

Or:

P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.

b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)

= 1 -  P(a cell has +4 nickel-charged options)  '.' because +4 is only positive nickel charge greater than +3      

= 1 - 0.15

=  0.85

To summarize:

P(cell has at least one of the positive nickel-charged options) = 0.83!!!

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!

8 0
3 years ago
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