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Alika [10]
2 years ago
11

1/3(6x-3)-1/4(20x+8)=-6

Mathematics
1 answer:
cluponka [151]2 years ago
8 0

Answer:

x = 1.

Step-by-step explanation:

\frac{1}{3}(6x-3)-\frac{1}{4}(20x+8)=-6\\\\[Distribute the first fraction into the parenthesis.]\\((\frac{1}{3}*6x)-(\frac{1}{3}*3))-\frac{1}{4}(20x+8)=-6\\\\2x-1-\frac{1}{4}(20x+8)=-6\\\\[Distribute the second fraction into the parenthesis.]\\2x-1-((\frac{1}{4}*20x)+(\frac{1}{4}*8))=-6\\\\2x-1-5x-2=-6\\\\[Combine like terms.]\\-3x-3=-6\\\\[Add 3 to both sides.]\\-3x=-3\\\\[Divide both sides by -3.]\\x=1

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You add two equations together to eliminate a variable. This particular problem is nice, because it's already setup to eliminate X.

3x - 4y = 9
<span>-3x + 2y = 9
</span>
When we add these two together, 3x - 3x cancels each other out, leaving us with 0x, or nothing.

We continue with -4y + 2y (leaves us with -2y) and 9+9 (18).

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