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Tema [17]
3 years ago
8

Use the drawing tool(s) to form the correct answer on the provided graph.

Mathematics
1 answer:
Leno4ka [110]3 years ago
7 0
Hello,
Please, see the attached file.
Thanks.

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Write a trinomial whose binomial factors contain constant terms that sum to −11 and have a product of 18.
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How many ways are possible to choose 3 days out of February? NOTE: Use 28 days for the number of days in February. A) 3276 B) 37
Charra [1.4K]

Answer:

A) 3,276 ways.

Step-by-step explanation:

In this case, choosing February 1, February 12, and February 20 would be the same thing as choosing February 12, February 1, and February 20. So, since order does not matter, we will use a combination to solve the question.

The formula for combinations is...

n! / [r!(n - r)!], where n = the number of days in February (28) and r = the number of days you are choosing (3).

28! / [3! * (28 - 3)!]

= 28! / (6 * 25!)

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Hope this helps!

5 0
3 years ago
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