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Eddi Din [679]
2 years ago
9

Madonna and Bruce Springsteen had the two top-grossing concert tours for 2012, together generating about $427 million in ticket

sales. If Bruce took in $29 million less than Madonna, how much did each tour generate?
Mathematics
1 answer:
Maru [420]2 years ago
8 0
427,000,000 / 2 = 213,500,00
213,500,00 - 29,000,000 = 184,500,00

Bruce took in $184,500,00
Madonna took in £213,500,000
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Answer 1,2 and 3 and challenge thank you
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Which of the following is x=-5 a solution ?
Katarina [22]

Answer:

C and D

Step-by-step explanation:

Plug X in and see which equations/expressions are true

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2 years ago
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PLEASE HELP ME WILL MARK BRAINLIEST! Town planners are planning a 500 foot by 700 foot parking lot by making a scale drawing tha
Scilla [17]

Answer:

The approximate value of the scale is 1:67

or the actual value without approximation is 1: 66 2/3 ( 66 while number , two over three)

Step-by-step explanation:

Here, we want to figure out the scale in inches of the drawing to the actual object.

The actual object is 500 ft by 700 ft

while the drawing is 90 inches by 126 inches

Mathematically, we know that 12 inches = 1 foot

So the actual object will be;

500(12) by 700(12)

= 6000 inches by 8400 inches

Now let’s make a division to get the scale;

6000/90 by 8400/126

we get 66.67 as answers on both ends

This is approximately equal to 67

So the scale we have here is 1:67

5 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
2 years ago
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