Answer:
64√3 ft²
Step-by-step explanation:
The short leg of the triangle has length (8 ft)(cos 60°), or (8 ft)(1/2), or 4 ft.
The long leg (represented by the dashed line) is (8 ft)(sin 60°), or
(8 ft)(√3/2), or 4√3. This is also the width of the horizontal trapezoid.
The area of this horizontal trapezoid is:
(sum of horizontal sides)
A = ------------------------------------- * (width)
2
Here, the area is:
(18 ft + (18 ft - 4 ft)
= ------------------------------------- * (4√3)
2
32 ft
= ----------- * 4√3 = 64√3 ft²
2
Inscribed angles are pretty easy, they're always half the corresponding central angle. The arc measure are always of central angles.
1. We're told to arc is 62 degrees so the inscribed angle is half,
WXY = 31 degrees.
2. Here we're told the inscribed angle is 113 degrees so the arc is double,
DGF=226 degrees
3. Angles which subtend a diameter are always right angles.
PQR = 90 degrees
4. If we draw DC we see it's a radius too, so DC=DB and we have an isosceles triangle so DCB=47 degrees so BDC=180-47-47=86. The central angle is the arc measure so
BC=86 degrees
5. Angle JNK=53 degrees and angles NJK=NKJ because we have an isosceles triangle, two sides radii. So NKJ=(180-53)/2.
Similarly NKL=(180-65)/2
So angle JKL=NKJ+NKL=180 - (65+53)/2 = 180 - 118/2 = 121 degrees
I better leave the rest for you.
Answer:
Area=15in²
Perimeter=16in
Step-by-step explanation:
area=L×W
Perimeter=L+L+W+W
Ok and? What’s the question?
