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alukav5142 [94]

3 years ago

13

Is the given conjecture a valid rule for the following sequence? If not, give a counterexample. Sequence: 1, 2, 3, 6, 18, 108, .

.. Conjecture: Multiply the previous 2 terms to get the next term

2 answers:

Rufina [12.5K]3 years ago

7 0

A counterexample is seen in the third term, 3, which does not equal 1*2=2.

1*2=2 NOT 3

Allushta [10]3 years ago

3 0

<span>No; 3 is a counterexample. is what i got

</span>

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Solve the following system of equations. Enter the y-coordinate of the solution. Round your answer to the nearest tenth.

ankoles [38]

Lets try substitution5x+2y=21=5x=21-2y=x=(21-2y)/5

sub into second equation

-2(21-2y)/5+6y=-34(-42+4y)/5+6y=-34solve for yy=-64/17plug into equation and solve for x=(97/17)

7 0

3 years ago

Read 2 more answers

The length of time before a seed germinates when falling on fertile soil is approximately Normally distributed with a mean of 60

PIT_PIT [208]

Answer:

b. 0.12

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 600, \sigma = 100$

What is the probability that a seed will take more than 720 hours before germinating?

This is 1 subtracted by the pvalue of Z when X = 720. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{720 - 600}{100}$

$Z = 1.2$

$Z = 1.2$ has a pvalue of 0.88.

1 - 0.88 = 0.12

So the correct answer is:

b. 0.12

4 0

3 years ago

Solve the system by graphing. Write the solution as an ordered pair.

Ierofanga [76]

( .467, 1.6 )
There is a website called desmos.com and if you put these equations in there it will find the intercepting point of these lines.
Hopefully this helps you!!

7 0

4 years ago

Sally is at the park standing directly under a kite which is 20 feet overheadSally's dad is flying the kitc and is standing 15 f

sergij07 [2.7K]

Answer:

25 feet

Step-by-step explanation:

Given that Sally is at the park standing directly under a kite which is 20 feet overheadSally's dad is flying the kitc and is standing 15 feet from her If both are on level ground, how long is the kite string in feet?

To calculate the length of the kite string, we will apply pythagorean theorem.

Length = sqrt ( 20^2 + 15^2 )

Length = sqrt ( 400 + 225 )

Length = sqrt ( 625 )

Length = 25 feet.

Therefore, the length of the kite string is 25 feet.

8 0

3 years ago

Please help! will give brainliest !!

Veseljchak [2.6K]

Answer:

1, 2, 8, 128, 32768

Step-by-step explanation:

$recursive \: formula: \\ a _{n} = 2. {( a_{n - 1} )}^{2} \\ \\ a _{1} = 1...(given) \\ \\ a _{2} = 2. {( a_{2 - 1} )}^{2} = 2 {(a _{1} )}^{2} = 2 {(1)}^{2} \\ \\ a _{2} = 2\\ \\a _{3} = 2. {( a_{3 - 1} )}^{2} = 2 {(a _{2} )}^{2} = 2 {(2)}^{2} \\ \\ a _{3} = 8\\ \\a _{4} = 2. {( a_{4 - 1} )}^{2} = 2 {(a _{3} )}^{2} = 2 {(8)}^{2} \\ \\ a _{4} = 128\\ \\a _{5} = 2. {( a_{5 - 1} )}^{2} = 2 {(a _{4} )}^{2} = 2 {(128)}^{2} \\ \\ a _{5} = 32,768\\ \\$

Thus the first five terms are: 1, 2, 8, 128, 32768.

5 0

3 years ago