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Alekssandra [29.7K]
3 years ago
8

The question is the picture

Mathematics
1 answer:
BabaBlast [244]3 years ago
7 0
Tha answer is 80+45+1.00
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Suppose you want to accumulate $25,000 as down payment on a house and the best you can do is to put aside $200 a month. If you d
Sunny_sXe [5.5K]

Answer:

It will take 88.2 months to accumulate the amount

Step-by-step explanation:

Given;

Future value of money, FV = $25,000

investment per compound period, P = $200

interest rate, i = 0.75% x 12 = 9%

The number of monthly installments required to amount to FV is given by;

n = \frac{ln(FVi +cp)-ln(cp)}{ln(c+i)-ln(c)}\\\\ n = \frac{ln(25000*0.09 +200*12)-ln(200*12)}{ln(12+0.09)-ln(12)}\\\\n = \frac{8.4446 -7.7832}{2.4924-2.4849}\\\\n = 88.2 \ months

Therefore, it will take 88.2 months to accumulate the amount.

7 0
4 years ago
Help me help help help help help
Blababa [14]

Answer:

d) 500 scoops

Step-by-step explanation:

looking at the trend of scoops sold per year, 500 seems to be the correct answer. let me know if this is wrong.

8 0
3 years ago
Read 2 more answers
PLEASE HELP due soon!I forgot how to do it omg
Flura [38]

Answer:

(3, -3) is correct

Step-by-step explanation:

-4 × 3 = -12. -12 + 9 = -3

8 0
3 years ago
The ordered pair (−3,−6) is a solution for the first equation, and it is a solution for the second equation. Therefore, (−3,−6)​
Alisiya [41]
False. If x=-3 and y=-6 and you substitute them into the equation they do not add up

7 0
3 years ago
Read 2 more answers
When Mya looked out at the store's parking lot, she noticed that for every 4 cars, there were 6 trucks. If there's a total of 22
olasank [31]

Answer:

<h2>88 cars</h2><h2>132 trucks</h2>

Step-by-step explanation:

This is a ratio problem, the ratio of  cars to trucks

for every 4 cars, there are 6 trucks

represented as a ratio we have 4:6

1. how many of them are cars

applying the part to whole strategy we have

4+6 = 10

let cars be x

\frac{4}{10}= \frac{x}{220}  \\\\x= \frac{220*4}{10} \\\\x= 880/10\\\\x= 88 cars

2.  how many of them are trucks?

let trucks be y

\frac{6}{10}= \frac{y}{220}  \\\\x= \frac{220*6}{10} \\\\y= 1320/10 \\\\y= 132 trucks

3 0
3 years ago
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