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Mashutka [201]
3 years ago
7

Please show your work this question what made you come to the conclusion. Thank you

Mathematics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

B the range, the x- and y-intercept

Step-by-step explanation:

the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).

but the range changes, as for the original function y could only have positive values - even for negative x.

the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.

the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.

the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.

the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.

the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)

3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

log_{b}(2 \div 3)  = x + 1

x =  log_{b}(2 \div 3)  - 1

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2 years ago
(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde
monitta

Using the distance formula, d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

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Plug this into a calculator and you get 6.32455532

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<em>Five or more, let it soar. Four or less, let it rest.</em>

Since two is lower than four, we drop it.

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