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Mashutka [201]
3 years ago
7

Please show your work this question what made you come to the conclusion. Thank you

Mathematics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

B the range, the x- and y-intercept

Step-by-step explanation:

the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).

but the range changes, as for the original function y could only have positive values - even for negative x.

the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.

the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.

the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.

the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.

the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)

3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

log_{b}(2 \div 3)  = x + 1

x =  log_{b}(2 \div 3)  - 1

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Step-by-step explanation:

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3 years ago
K is the midpoint of JL JK=3x-1 and KL=2x+8 find JL
Masteriza [31]

Answer:

JL = 52

Step-by-step explanation:

It is given in the question that K is the midpoint of JL.

So, JK = KL ......... (1)

Now, given that, JK =3x - 1 and KL = 2x + 8  

Therefore, from equation (1), we can write  

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So, JK = 3x - 1 = 3(9) -1 = 26 and KL = 2x + 8 = 2(9) + 8 = 26

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3 0
3 years ago
Anyways I’m so close! Sleep here I come lol
a_sh-v [17]

Answer:

558

Step-by-step explanation:

930

x 0.40

-------------

372

Next

372

-930

-----------

558

Hope this helped!

3 0
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