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3 years ago

What does the cursive r thing mean

Mathematics

2 answers:

arsen [322]3 years ago

7 0

Whatttttttttt I don't get what you are trying to say but cursive means a right print r a normal r

Kobotan [32]3 years ago

3 0

The cursive R means R

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Hey can you help me fast!!!

kotykmax [81]

Answer:

12 ft²

Step-by-step explanation:

the rectangular hole area:

l • w = A

3 • 2 = 6 ft

the triangular hole area:

(b • h) / 2 = A

(4 • 3) / 2 = 6 ft

6 ft + 6 ft = 12 ft²

7 0

2 years ago

On a map, Maya uses a ruler to find the approximate distance between her town and Los Angeles. The distance on the map is 25 cm.

zlopas [31]

Answer:

Scale of the Map = 1 cm to 82 Km

Step-by-step explanation:

25cm is equivalent to 2050Km

Hence 1cm will be equivalent to 2050/25 = 82Km

7 0

3 years ago

Read 2 more answers

The slang height of a right circular cone is 9 meters and the radius of the base is 5 meters. What is the surface area of the co

juin [17]

Answer:

So i say C

Step-by-step explanation:

240 = area

7 0

2 years ago

Use the Chain Rule (Calculus 2)

atroni [7]

1. By the chain rule,

$\dfrac{\mathrm dz}{\mathrm dt}=\dfrac{\partial z}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial z}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}$

I'm going to switch up the notation to save space, so for example, $z_x$ is shorthand for $\frac{\partial z}{\partial x}$ .

$z_t=z_xx_t+z_yy_t$

We have

$x=e^{-t}\implies x_t=-e^{-t}$

$y=e^t\implies y_t=e^t$

$z=\tan(xy)\implies\begin{cases}z_x=y\sec^2(xy)=e^t\sec^2(1)\\z_y=x\sec^2(xy)=e^{-t}\sec^2(1)\end{cases}$

$\implies z_t=e^t\sec^2(1)(-e^{-t})+e^{-t}\sec^2(1)e^t=0$

Similarly,

$w_t=w_xx_t+w_yy_t+w_zz_t$

where

$x=\cosh^2t\implies x_t=2\cosh t\sinh t$

$y=\sinh^2t\implies y_t=2\cosh t\sinh t$

$z=t\implies z_t=1$

To capture all the partial derivatives of $w$ , compute its gradient:

$\nabla w=\langle w_x,w_y,w_z\rangle=\dfrac{\langle1,-1,1\rangle}{\sqrt{1-(x-y+z)^2}}}=\dfrac{\langle1,-1,1\rangle}{\sqrt{-2t-t^2}}$

$\implies w_t=\dfrac1{\sqrt{-2t-t^2}}$

2. The problem is asking for $\frac{\partial z}{\partial x}$ and $\frac{\partial z}{\partial y}$ . But $z$ is already a function of $x,y$ , so the chain rule isn't needed here. I suspect it's supposed to say "find $\frac{\partial z}{\partial s}$ and $\frac{\partial z}{\partial t}$ " instead.

If that's the case, then

$z_s=z_xx_s+z_yy_s$

$z_t=z_xx_t+z_yy_t$

as the hint suggests. We have

$z=\sin x\cos y\implies\begin{cases}z_x=\cos x\cos y=\cos(s+t)\cos(s^2t)\\z_y=-\sin x\sin y=-\sin(s+t)\sin(s^2t)\end{cases}$

$x=s+t\implies x_s=x_t=1$

$y=s^2t\implies\begin{cases}y_s=2st\\y_t=s^2\end{cases}$

Putting everything together, we get

$z_s=\cos(s+t)\cos(s^2t)-2st\sin(s+t)\sin(s^2t)$

$z_t=\cos(s+t)\cos(s^2t)-s^2\sin(s+t)\sin(s^2t)$

8 0

2 years ago

Plz help with 6,7,8 and 9

Reil [10]

Grayson's mistake was that he multiplied 4 and 3 and then used the exponent he had to square 3 and then multiply it by 4.

Emily's mistake was that she added 2 to 36 instead of multiplying it by -2

Pat's mistake was that he forget to make y into -2 instead of 2

The right way to do this is 4(3^2)+2(-2)
(3^2)=9 9×4=36 2(-2)=-4 -4+9=5

3 0

2 years ago