1,5,9,13,17,21,25,29..., 4n+1
in general terms of an arithmetic sequence with the first term A0 and common differences d,
If you are answering a question or about how many pages he has in his book, it is 550 pages in his book total. If it's how much longer Naoya will have to read to finish their book it is 10 hours.
The matrix that represents the matrix D is ![\left[\begin{array}{cccc}3&1&-9&8\\2&2&0&5\\16&1&-3&11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%26-9%268%5C%5C2%262%260%265%5C%5C16%261%26-3%2611%5Cend%7Barray%7D%5Cright%5D)
<h3>How to determine the matrix d?</h3>
Given the elements of the matrix C.
The matrix c is represented by its rows and columns element, and the arrangements are:
C11 = 3 C12 = 1 C13=-9 C14 = 8
C21 = 2 C22=2 C23 =0 C24 = 5
C31 = 16 C32 = 1 C33=-3 C34=11
Remove the matrix name and position
3 1 9 8
2 2 0 5
16 1 -3 11
Represent properly as a matrix:
![C = \left[\begin{array}{cccc}3&1&-9&8\\2&2&0&5\\16&1&-3&11\end{array}\right]](https://tex.z-dn.net/?f=C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%26-9%268%5C%5C2%262%260%265%5C%5C16%261%26-3%2611%5Cend%7Barray%7D%5Cright%5D)
Matrix C equals matrix D.
So, we have:
![D = \left[\begin{array}{cccc}3&1&-9&8\\2&2&0&5\\16&1&-3&11\end{array}\right]](https://tex.z-dn.net/?f=D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%26-9%268%5C%5C2%262%260%265%5C%5C16%261%26-3%2611%5Cend%7Barray%7D%5Cright%5D)
Hence, the matrix that represents matrix D is ![\left[\begin{array}{cccc}3&1&-9&8\\2&2&0&5\\16&1&-3&11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%26-9%268%5C%5C2%262%260%265%5C%5C16%261%26-3%2611%5Cend%7Barray%7D%5Cright%5D)
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Answer: $409.55
Step-by-step explanation:
100% - 16% = 84%
84% of 487.56 = 409.5504.
Round to nearest hundredth.
$409.55
Answer:
The cup can hold 497.17 in³ of liquid.
Step-by-step explanation:
The shape of the glass can be divided in two figures, the first one is a cilinder with radius 5 in and height 3 in, while the second is a half sphere with radius 5 in. Therefore in order to calculate the volume of liquid the glass can hold we need to calculate the volume of each of these and sum them.
Vcilinder = pi*r²*h = 3.14*5²*3 = 235.5 in³
Vhalfsphere = (2*pi*r³)/3 = (2*3.14*5³)/3 = 261.67 in³
Vcup = Vcilinder + Vhalfsphere = 235.5 + 261.67 = 497.17 in³
The cup can hold 497.17 in³ of liquid.