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ira [324]
3 years ago
15

The height of one square pyramid is 12 m. A similar pyramid has a height of 6 m. The volume of the larger pyramid is 400 m3. Det

ermine each of the following, showing all your work and reasoning.
Scale factor of the smaller pyramid to the larger pyramid in simplest form

Ratio of the areas of the bases of the smaller pyramid to the larger pyramid

Ratio of the volume of the smaller pyramid to the larger

Volume of the smaller pyramid
Mathematics
1 answer:
tatiyna3 years ago
7 0
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\


\bf \cfrac{smaller}{larger}\qquad \cfrac{\stackrel{height}{6}}{\stackrel{height}{12}}\implies \cfrac{1}{2}\impliedby \textit{scale factor of the pyramids}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{h}{h}=\cfrac{\sqrt{base}}{\sqrt{base}}\implies \cfrac{1}{2}=\sqrt{\cfrac{base}{base}}\implies \left( \cfrac{1}{2} \right)^2=\cfrac{base}{base}
\\\\\\
\cfrac{1^2}{2^2}=\cfrac{base}{base}\implies \cfrac{1}{4}=\cfrac{base}{base}\\\\
-------------------------------\\\\

\bf \cfrac{smaller}{larger}\qquad \cfrac{h}{h}=\cfrac{\sqrt[3]{volume}}{\sqrt[3]{volume}}\implies \cfrac{1}{2}=\sqrt[3]{\cfrac{volume}{volume}}
\\\\\\
\left( \cfrac{1}{2} \right)^3=\cfrac{volume}{volume}
\implies 
\cfrac{1^3}{2^3}=\cfrac{volume}{volume}\implies \cfrac{1}{8}=\cfrac{volume}{volume}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{1}{8}=\cfrac{\stackrel{volume}{v}}{\stackrel{volume}{400}}\implies \cfrac{1\cdot 400}{8}=v
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Solving a system of equations, we can see that:

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  • Speed of the commercial jet: 192mi/h

<h3>How to find the speeds of each jet?</h3>

Let's define the variables:

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  • C = speed of the commercial jet.

With the given information, we can write:

P*8h = D

C*7h = D

C = 2*P - 144mi/h

So we have a system of 3 equations, where D is the distance in the problem.

With the first and second equations we can write:

P*8h = D = C*7h

Isolating P, we get:

P = C*(7/8)

Now we can replace that in the last equation:

C = 2*P - 144mi/h

C = 2*C*(7/8) - 144mi/h

And now we can solve that for C.

C - 2*(7/8)*C = - 144mi/h

C*(1 - 14/8) = -144mi/h

C*(8/8 - 14/8) = - 144mi/h

C*(6/8) = 144mi/h

C = (8/6)*144mi/h = 192mi/h

Now that we know the speed of the commercial jet, we can find the speed of the private jet.

P = C*(7/8) = 192mi/h*(7/8) = 168 mi/h

If you want to learn more about systems of equations:

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6 0
2 years ago
Please help me guys, thanks
mr_godi [17]

Answer:

R = 0.06

Step-by-step explanation:

Hello

If, I = PRT

then,

900 = (7500)*R*2

R = 900/15000

R = 0.06

Best regards

6 0
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<u>The growth factor</u>:

   ⇒ <em>is the </em><u><em>base in the exponent</em></u><em>:</em>

<em>        ⇒ the larger it is ⇒ the greater the growth factor is!</em>

<em />

<u>Let's Analyze our choices:</u>

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<u>The greatest growth factor is 3</u>

<u />

<u>Answer: d(t)</u>

<u></u>

Hope that helps!

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