Answer:
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = 0.1251
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given mean of the Population = 25cm
Given standard deviation of the Population = 2.60
Let 'x' be the random variable in normal distribution
Given x=22
<u><em>Step(ii):</em></u>-
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = P( Z<-1.15)
= 1-P(Z>1.15)
= 1-( 0.5+A(1.15)
= 0.5 - A(1.15)
= 0.5 - 0.3749
= 0.1251
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = 0.1251
120$. 100%
X$. 8.33%
X= 120• 8.33/100
X=9.99 $
Answer:
<em>x </em>equals 3.6.
Step-by-step explanation:
A way to solve this equation is to preform the inverse operations on both sides.
1. Add 19 to -19 and 5: 5<em>x </em>+ 6 - 19 + 19 = 5 + 19 ---> 5x + 6 = 24
2. Subtract 6 from 6 and 5: 5x + 6 - 6 = 24 - 6 ---> 5x = 18
3. Divide 5x and 18 by 5: 5x / 5 = 18 / 5 ---> x = 3.6
4. 3.6 is the answer.
To prove it, substitute x with 3.6 in the equation: 5 · 3.6 + 6 - 19 = 5
I hope this made sense and helped you a lot! :)
*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*
(21)
Area of a Regular Hexagon: 
square units
(22)
Similar to (21)
Area = 
square units
(23)
For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:
Hence, area of the hexagon will be: 
square units
(24)
Given is the inradius of an equilateral triangle.
Substituting the value of inradius and calculating the length of the side of the equilateral triangle:
Side = 16 units
Area of equilateral triangle = 
square units
Answer:
Equations are composed for many expressions.
Expressions can indicate variables, constants, etc.
Best regards
