Question

Noa drove from the Dead Sea up to Jerusalem, and her altitude increased at a constant rate of 740 meters per hour. When she arrived in Jerusalem after 1.5 hours of driving, her altitude was 710 meters above sea level.
Let A(t) denote Noa's altitude relative to sea level A (measured in meters) as a function of time t (measured in hours).

Answer 1

Hmm, so

A(t)=740t+a₀
where a₀ is initial height or the height she started at

we want to find her initial height

after 1.5 hours, she was 710 meters above sea levl
alright
A(1.5)=740(1.5)+a₀=710
740(1.5)+a₀=710
1110+a₀=710
minus 1110 both sides
a₀=-400


so she stared at -400 meters below sea level

and the equation would be (or function)
A(t)=740t-400

Answer 2

Answer:

Model of path which Noa drove, A(t)=740t-400

Step-by-step explanation:

Noa drove from the Dead Sea up to Jerusalem, and her altitude increased at a constant rate of 740 meters per hour.

Therefore, slope (m) = 740 m/s

Let point (t,A)

Where, t is time to reach at A height from sea level

She arrived at 710 m in 1.5 hours

Therefore, Point (1.5,710)

Now we will use the formula of line point-slope form.

$y-y_1=m(x-x_1)$

Equation of path:

$A(t)=740(t-1.5)+710$

$A(t)=740t-1110+710$

$A(t)=740t-400$

Thus, Model of path Noa drove.A(t)=740t-400