How do we transform system a into system b? <br> THIS IS KOT MULTIPLE CHOICE. PLEASE ANSWER ASAP!!

MakcuM [25]

Answer:

Hello! Your answer is, A) The arrow pointing to the right

Step-by-step explanation:

Hope I helped! Ask me anything if you have any questions! Brainiest plz! Hope you make an 100% and have a wonderful day! -Amelia♥

5 0

3 years ago

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Find the product of 30−−√ and 610−−√. Express it in standard form (i.E., ab√).

Zina [86]

we are given

$\sqrt{30} *\sqrt{610}$

we can radical formula

$\sqrt{a} *\sqrt{b}=\sqrt{a*b}$

we get

$\sqrt{30} *\sqrt{610}=\sqrt{30*610}$

$\sqrt{30} *\sqrt{610}=\sqrt{3*61*100}$

we can also write as

$\sqrt{30} *\sqrt{610}=\sqrt{100}*\sqrt{3*61}$

$\sqrt{30} *\sqrt{610}=10\sqrt{183}$ ............Answer

7 0

3 years ago

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What is the equation of the circle with center (5,-4) and containing the points (5,-2)

gtnhenbr [62]

Answer:

The equation of a circle is $(x-5)^2+(y+4)^2=4$ .

Step-by-step explanation:

-The equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$ (where center is $(h,k)$ , the point $(x_{1},y_{1})$ and the radius known as $r$ ).

-Use the center (5,-4) and the point (5,-2) for the equation:

$(5-5)^2+(-2+4)^2=r^2$

-Solve the equation:

$(5-5)^2+(-2+4)^2=r^2$

$0 + (-2)^2=r^2$

$4 = r^2$

$\sqrt{4} = \sqrt{r^2}$

$2 = r$

-After you found the radius, use the center (5, -4) and radius 2 to get the equation of a circle:

$(x-5)^2+(y+4)^2=2^2$

-Then, after you have the equation, the radius needs to simplified by the exponent:

$(x-5)^2+(y+4)^2=4$

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =

Georgia [21]

Answer: $\dfrac{1}{2\sqrt x}$

<u>Step-by-step explanation:</u>

$\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}$

f(x) = $\sqrt x\\$

f(x+h) = $\sqrt{x+h}$

$\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}$

$=\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)$

$=\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{1}{\sqrt{x+h}+\sqrt x}$

$=\dfrac{1}{\sqrt{x+0}+\sqrt x}$

$=\dfrac{1}{2\sqrt x}$

4 0

3 years ago

Divide both sides of 15=5x by 5 what is the result

svetlana [45]

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8 0

2 years ago

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How do we transform system a into system b? THIS IS KOT MULTIPLE CHOICE. PLEASE ANSWER ASAP!!