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garik1379 [7]
4 years ago
11

CONSUMER MATH HELP!!!

Mathematics
2 answers:
kifflom [539]4 years ago
6 0
The answer to #1 is D.

The answer to #2 I believe is B. Closing Costs
Hoochie [10]4 years ago
6 0

Answer:

1. Which example is NOT a type of savings instrument?

The answer is : checking account. A checking account is an account that people keep to maintain their day to day expenses. The money can be taken out by using atm cards or using checks.

2. CLOSING COST is the amount paid when you purchase a home that covers additional expenses like taxes and title fees. This closing cost is the final deal close amount in real estate section.

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A concession stand sells hamburgers (h) for $2 and hotdogs(d) for $1.On friday night they sold a total of 300 hamburgers and hot
Olegator [25]
The first equation has to be the sum of hotdogs and hamburgers. Since a total of 300 <span>hamburgers and hotdogs was sold, the first equation is:
          h+d=300

Now, the second equation is about the money. They say that EACH hamburger cost $2 and each hotdog cost $1. And, the total amount of money made was $420. So the second equation is:

      2h+d=420

SO, overall, the system of equations is this:

   
h+d=300
   2h+d=420
     
(option A is the answer)
</span>
8 0
4 years ago
Does this problem have a constant rate?
Marina86 [1]
Yes, as x grows by 1 y grows by -2 (or decreases by 2!)
3 0
3 years ago
Read 2 more answers
Help please math answer ASAP NO LINKS
Sidana [21]

5/11 is a fraction, so it is for sure a rational number and a real number.

Since it is a fraction, it is NOT irrational (which means "not rational" or "not a fraction).

It is NOT an integer, whole number, or natural number, becuase it is only a piece of a whole.  5/11 ≈ 0.454545..., and intergers, whole numbers, and natural numbers don't involve decimals.

5 0
3 years ago
Read 2 more answers
Nickel-63 is a radioactive substance with a half-life of about 100 years. An artifact had
Marina CMI [18]

Answer:

see below

Step-by-step explanation:

The equation for half life is

n = no  e ^ (-kt)

Where no is the initial amount of a substance , k is the constant of decay and t is the time

no = 9.8

1/2 of that amount is 4.9 so n = 4.9 and t = 100 years

4.9 = 9.8 e^ (-k 100)

Divide each side by 9.8

1/2 = e ^ -100k

Take the natural log of each side

ln(1/2) = ln(e^(-100k))

ln(1/2) = -100k

Divide each side by -100

-ln(.5)/100 = k

Our equation in years is

n = 9.8  e ^ (ln.5)/100 t)

Approximating ln(.5)/100 =-.006931472

n = 9.8 e^(-.006931472 t)  when t is in years

Now changing to days

100 years = 100*365 days/year

36500 days

Substituting this in for t

4.9 = 9.8 e^ (-k 36500)

Take the natural log of each side

ln(1/2) = ln(e^(-36500k))

ln(1/2) = -36500k

Divide each side by -100

-ln(.5)/36500 = k

Our equation in years is

n = 9.8  e ^ (ln.5)/36500 d)

Approximating ln(.5)/365=-.00001899

n = 9.8 e^(-.00001899 d)  when d is in days

3 0
4 years ago
Read 2 more answers
9.<br><br><br>A. (3, 6)<br><br>B. (20, –4)<br><br>C. (10, –1)<br><br>D. (–1, 8)
crimeas [40]

Answer:

(10, –1)

Step-by-step explanation:

[1]XXXX3y=−12x+2

[2]XXXXy=−x+9

While it is not technically necessary, I find it easier to clear the fractions before actually beginning; so multiplying [1] by 2

[3]XXXX6y=−x+4

Substituting (from [2]) (−x+9) for y in [3]

[4]XXXX6(−x+9)=−x+4

Simplifying

[5]XXXX−6x+54=−x+4

[6]XXXX5x=50

[7]XXXXx=10

Substituting (from [7]) 10 for x in [2]

[8]XXXXy=−10+9=−1

7 0
3 years ago
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