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3 years ago

CONSUMER MATH HELP!!!

Mathematics

2 answers:

kifflom [539]3 years ago

6 0

The answer to #1 is D.

The answer to #2 I believe is B. Closing Costs

Hoochie [10]3 years ago

6 0

Answer:

1. Which example is NOT a type of savings instrument?

The answer is : checking account. A checking account is an account that people keep to maintain their day to day expenses. The money can be taken out by using atm cards or using checks.

2. CLOSING COST is the amount paid when you purchase a home that covers additional expenses like taxes and title fees. This closing cost is the final deal close amount in real estate section.

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8-2d=x please solve this for me i need it right now!!!!!!!!

olga_2 [115]

Answer: You need more information to solve this, is there another part of the question?

Step-by-step explanation:

3 0

2 years ago

Find the distance between (10, 12) and (1,0

Luba_88 [7]

Answer:

The desired distance is 15 units.

Step-by-step explanation:

Note how x increases from 1 to 10 and y from 0 to 12 at the same time.

Using the Pythagorean Theorem, we find that the distance between the two points is the length of the hypotenuse, which is

d = √[ (10 - 1)^2 + (12 - 0)^2 ], or d = √ [81 + 144] = 225 = +15

The desired distance is 15 units.

8 0

2 years ago

Addison paid $1.29 for gum and $0.89 for a package of notebook paper . She gave the cashier a $5 bill. If the tax was $0.14, how

GenaCL600 [577]

Ok....

$1.29 + $0.89 = $2.18

Subtract $2.18 from $5.00 and you get: $2.82

If Addison was charged an extra $0.14 in tax, she'll be given $2.82 - $0.14 in change.

Answer:

$2.68

7 0

3 years ago

A student was trying to find the solution to a system of equations, but they were incorrect. Their explanation is shown below.

Lady_Fox [76]

Answer:

no solution

Step-by-step explanation:

if you subtract the equations then you get 0 = 8 and this can never be true; therefore there are no solution

7 0

2 years ago

1. The width w of a rectangular swimming pool is x+4. The area A of the pool is 2x^3-29+12. what is an expression for the length

hjlf

** CORRECTIONS: Q1: It's 2x^3-29x+12; Q2,3,4,5,6: All conditions have ≠ symbol; Q7: it's (12x^2+32x+16); Q10: Option D should be divided by x^4; **

(1) Given:

Width = W = x+4

Area = A = $2x^3-29x+12$

Length = L = ?

Since the pool is rectangular in shape:

area = width * length

A = W * L

Substitute:

$2x^3-29x+12 = (x+4) * L \\ L =\frac{2x^3-29x+12}{x+4}$

The long division is attached with the answer (below in the picture). Hence the correct answer is $2x^2-8x+3$ (Option C)

(2) Given expression:

$\frac{x}{6x-x^2} \\ \frac{x}{x(6-x)} \\ \frac{1}{6-x}$

Where x ≠ 6. (Option B)

(3) Given :

$\frac{-12 x^{4} }{x^{4}+8 x^{5} }$

Now simplify:

$\frac{-12 x^{4} }{x^{4}+8 x^{5} }= \frac{-12 x^{4} }{ x^{4}(1+8x)}= \frac{-12}{1+8x}$

Where x ≠ -1/8 (Option A)

(4) Given:

$\frac{x+5}{x^{2}+6x+5}$

Simplify:

$\frac{x+5}{x^{2}+6x+5}= \frac{x+5}{(x+1)(x+5)}= \frac{1}{x+1}$

Where x ≠ -1 (Option A)

(5) Given:

$\frac{x^{2}-3x-18} {x+3}$

Simplify:

$\frac{x^{2}-3x-18} {x+3}= \frac{(x-6)(x+3)}{x+3}= \frac{x-6}{1}=x-6$ where x≠6 (Option C)

(6) Given:

$\frac{2}{3a} .\frac{2}{a^2}$

Simplify:

$\frac{4}{3a^{1+2}} = \frac{4}{3a^{3}}$

Where a ≠ 0 (Option C)

(7) Mathematically:

$\frac{x-5}{4x + 8} * (12x^2+32x+16)$

Simplify:

$\frac{x-5}{4x + 8} * (12x^2+32x+16) \\ \frac{x-5}{4(x + 2)} * 12x^2 + \frac{x-5}{4(x + 2)} * 32x + \frac{x-5}{4(x + 2)} * 16 \\ \frac{x-5}{(x + 2)} * 3x^2 + \frac{x-5}{(x + 2)} * 8x + \frac{x-5}{(x + 2)} * 4 \\ \frac{(x-5)(3x^2 + 8x + 4x) }{(x+2)} \\ \frac{(x-5)(3x^2 -6x - 2x + 4x) }{(x+2)} \\ \frac{(x-5)(3x+2)(x+2) }{(x+2)} \\ =(x-5)(3x+2)$

(Option C)

(8) Simplify:

$\frac{( \frac{x^{2}-16} {x-1}) }{(x+4)} \\ \frac{( \frac{(x+4)(x-4)} {x-1}) }{(x+4)} \\ = \frac{(x-4)} {(x-1)}$

(Option A)

(9) Simplify:

$\frac{ \frac{x^2+2x+1}{x-2}}{\frac{x^2-1}{x^2-4 }} \\ \frac{ \frac{(x+1)(x+1)}{x-2}}{\frac{(x+1)(x-1)}{(x-2)(x+2) }} \\ \frac{ \frac{(x+1)}{1}}{\frac{(x-1)}{(x+2) }} \\ = \frac{(x+1)(x+2)}{(x-1)}$

(Option A)

(10) Given:

$\frac{24 w^{10}+8w^{12} }{4 x^{4} }$

Simplify:

$\frac{24 w^{10}+8w^{12} }{4 x^{4} }= \frac{24w^{10} }{4 x^{4} } + \frac{8 w^{12} }{4 x^{4} } = \frac{6w^{10} }{x^{4} }+ \frac{2w^{12} }{x^{4}}= \frac{6w^{10}+2w^{12} }{ x^{4}}$

(Option D)

(11) Given:

$\frac{-6m^{9}-6m^{8}-16m^{6} }{2m^{3} }$

Simplify:

$\frac{-6m^{9}-6m^{8}-16m^{6} }{2m^{3} } = \frac{-2m^{6}(3m^{3}+3m^{2}+8)}{2m^{3} } = -m^{3}(3m^{3}+3m^{2}+8)\\ = -3m^{6}-3m^{5}-8m^{3}$

(Option C)

(12) Simplify:

$\frac{-4x}{x+7} - \frac{8}{x-7} = \frac{-4x(x-7)-8(x+7)}{(x+7)(x-7)} \\ \frac{-4 x^{2} +28x-8x-56}{(x+7)(X-7)}= \frac{-4 x^{2} +20x-56}{(x+7)(x-7)} \\ \frac{(-4x+28)(x-2)}{(x+7)(x-7)} = \frac{-4(x-7)(x-2)}{(x+7)(x-7)} = \frac{-4x+8}{x+7}$

(Option A)

(13) Simplify:

$\frac{3}{x-3} - \frac{5}{x-2} \\ = \frac{x3(x-2)-5(x-2)}{y(x-3)(x-2)} \\ \frac{3x-6-5x+15}{(x-3)(x-2)} \\= \frac{-2x+9}{(x-3)(x-2)}$

(Option A)

(14) Simplify:

$\frac{9}{x-1}- \frac{5}{x+4}= \frac{9(x+4)-5(x-1)}{(x-1)(x+4)} \\ \frac{9x+36-5x+5}{(x-1)(x+4)}= \frac{4x+41}{(x-1)(x+4)}$

(Option B)

(15) Simplify:

$\frac{-3}{x+2}- \frac{(-5)}{x+3}\\= \frac{-3(x+3)-(-5)(x+2)}{(x+2)(x+3)} \\ = \frac{-3x-9+5x+10}{(x+2)(x+3)}\\= \frac{2x+1}{(x+2)(x+3)}$

(Option D)

(16) Given:

4/x + 5/x = -3

Simplify:

(4+5)/x = -3

-3x = 9

x = -3 (Option C)

(17) Simplify:

$\frac{1}{3x-6} - \frac{5}{x-2} = 12 \\ \frac{(x-2)-5(3x-6)}{(3x-6)(x-2)} = 12 \\ \frac{(x-2)-5*3(x-2)}{(3x-6)(x-2)} = 12 \\ \frac{-14(x-2)}{(3x-6)(x-2)} = 12 \\ \frac{-14}{(3x-6)} = 12\\ -14 = 12(3x-6) \\ -14 = 36x - 72 \\ 36x = 58 \\ x=\frac{29}{18}$

(Option D)

(18) Simplify:

$\frac{1}{x} - \frac{6}{x^2} = -12 \\ \frac{x - 6}{x^2} = -12 \\ x-6 = -12x^2 \\ 12x^2 + x - 6 = 0 \\ 12x^2 + 9x - 8x - 6 = 0 \\ 3x(4x + 3) -2(4x + 3) =0 \\ (3x-2)(4x+3) =0 \\ => x =\frac{2}{3} , x =\frac{-3}{4}$

(Option C)

(19) Dorothy's rate (alone) will be:

$R_D =\frac{1}{6}$

Rosanne's rate (alone) will be:

$R_R =\frac{1}{8}$

If both work together, add both the rates:

$R_T = R_D + R_R = \frac{1}{6} + \frac{1}{8} = \frac{7}{24}$ (in 1/hours)

To find the hours, flip the rate:

$\frac{24}{7} = 3.43$ hours (Option B)

(20) As pressure (p) is inversely proportional with volume (v):

p = k/v (where k is constant of proportionality)

k = pv

Find constant using initial values:

k = (104)(108)

k = 11232

Now new pressure is:

p = k/v = 11232/432 = 26 Pa (Option A)

(21)

x: 1,3,5,10

y: 4,12,20,40

Direct variation is the value of y increases with x. So,

y = 4x

If x = 1,y=4(1)=4

If x = 3,y=4(3)=12

If x = 5,y=20

If x = 10,y=40 (Option A)

(22) $\frac{3}{4x+64}$

If x=-16,4(-16) + 64 = 0;denominator will become zero,which means that there will be discontinuity at x = -16. Hence, x=-16 (Option C) should be excluded.

3 0

3 years ago

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