Axis of symmetry- x=-1
-b/2a
Mark brainliest please
Answer:
Step-by-step explanation:
A quarter circle is one fourth of a circle. To find the area of a quarter circle, find the area of the whole circle by using the formula A = pi * r^2 and then divide by 4. To find the perimeter of the quarter circle, find the circumference of the whole circle, divide by 4, and then add the radius twice.
As is the case for any polynomial, the domain of this one is (-infinity, +infinity).
To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,
The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.
Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).
In an isosceles triangle that has exactly two equal sides, the equal sides are called legs and the third side is called the base. The angle included by the legs is called the vertex angle and the angles that have the base as one of their sides are called the base angles.
Answer:
2
Step-by-step explanation:
