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dezoksy [38]
3 years ago
11

Use the graph of f (x)=|x| to write an equation for the function repesented by the graph

Mathematics
1 answer:
NikAS [45]3 years ago
7 0
See, please, the suggested explanation:
the equation is y= -|x+3|, where '-' means location of graph in the 3-d quarter, '+3' - the graph is moved to the left on 3 points.
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Need Help ASAp will give brainliest!!!
Elina [12.6K]

Answer:

0.05

Step-by-step explanation:

3.25 divided by 9 is 0.35 and 2.4 divided by 8 is 0.3 (0.30)

theres a 0.05 gap

if im wrong im sorry

6 0
3 years ago
A triangle has sides of length 4,3, and 5. is it a right triangle? explain
iVinArrow [24]
It is a right triangle because a 3, 4, 5 triangle is always a right triangle. it is because it is a Pythagorean Triple. all the sides are whole numbers
3 0
4 years ago
Read 2 more answers
How to make a box plot
Step2247 [10]
<h2>How to make a Box-and-whisker plot:</h2>
  1. organize your data points from least to greatest.
  2. find the median (middle number), as this will also be our second quartile (we have four in total.)
  3. find the first and third quartiles by finding the median of both the lower and upper halves made from the numbers left over from your previous median.
  4. draw a plot line and mark your quartiles with vertical lines and box them in.
  5. mark your outliers, the smallest and largest numbers with dots and connect them to your box
5 0
3 years ago
9 x 9 = 5 groups of 9 + ____ groups of 9 =
lukranit [14]
4;81
You subtract 5 from 9 to get 4; 5(9)= 45 9(4)=36 45+39=81
3 0
4 years ago
In ΔRST, the measure of ∠T=90°, SR = 65, TS = 33, and RT = 56. What is the value of the sine of ∠R to the nearest hundreth
irina [24]

We have been given that in ΔRST, the measure of ∠T=90°, SR = 65, TS = 33, and RT = 56. We are asked to find the value of sine of ∠R to the nearest hundreth.

First of all, we will draw a right triangle using our given information.  

We know that sine relates opposite side of right triangle to hypotenuse.

We can see that side SR is hypotenuse and TS is opposite side to angle R.

\sin(\angle R)=\frac{SR}{TS}

\sin(\angle R)=\frac{65}{33}

\sin(\angle R)=1.96969

Upon rounding to nearest hundredth, we will get:

\sin(\angle R)\approx 1.97

Therefore, the value of the sine of ∠R is approximately 1.97.

3 0
3 years ago
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