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3 years ago

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Find the surface area of a regular prism iwth height 6 cm, if the base of the prism is: Equilateral triangle with a side of leng

th 3 cm and height of the triangle of aproximately 2.6 cm long.

1 answer:

ser-zykov [4K]3 years ago

4 0

Answer:

61.8 square centimeters

Step-by-step explanation:

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Add −2/3+2 3/8 . Write your answer as a mixed number in simplest form.

d1i1m1o1n [39]

Answer:

41/24 or 1 17/24

Step-by-step explanation:

2 3/8=19/8

-2/3+19/8

-16/24+57/24

41/24

5 0

2 years ago

Read 2 more answers

prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.

Vsevolod [243]

Answer:

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ . If we know that $A(x,y) =(-1, 1)$ , $B(x,y) =(-3,4)$ , $C(x,y) = (1,5)$ and $D(x,y) = (3,2)$ , then the measure of each vector is, respectively:

$\overrightarrow{AB} = (-3,4)-(-1,1)$

$\overrightarrow{AB} = (-2, 3)$

$\overrightarrow{DC} = (1,5)-(3,2)$

$\overrightarrow{DC} = ( -2,3)$

$\overrightarrow{AD} = (3,2)-(-1,1)$

$\overrightarrow{AD} = (4, 1)$

$\overrightarrow{BC} = (1,5)-(-3,4)$

$\overrightarrow{BC} = (4, 1)$

Since $\overrightarrow{AB} = \overrightarrow{DC}$ and $\overrightarrow{AD} = \overrightarrow{BC}$ , then the quadrilateral ABCD is a parallelogram.

7 0

3 years ago

Make up two equations, one that is true and one that is false. do not state which equation is true and which is false.

Sophie [7]

3 + 6 = 9 - <span>1
4x3=36/3</span>

4 0

4 years ago

The points (3,0) and (6,4) are adjacent vertices of a square, What is the area of the square, in unit squared? HELP PLS

zaharov [31]

Answer: 25

<u>Step-by-step explanation:</u>

Find the distance from (3, 0) to (6,4). That is the side length (s).

Area (A) = s²

$s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\s^2=(x_2-x_1)^2+(y_2-y_1)^2\\\\s^2=(6-3)^2+(4-0)^2\\\\s^2=3^2+4^2\\\\s^2=9+16\\\\s^2=25\\\\\\A=s^2\\\\\large\boxed{A = 25}$

7 0

3 years ago

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The area of a triangular sign is 48 ft. If the base of the sign is 16 feet, what is the height of the sign?

Black_prince [1.1K]

Answer:

h=6ft

Step-by-step explanation:

A=(1/2)bh

48=16(1/2)h

3=(1/2)h

h=6ft

3 0

3 years ago