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2 years ago

8

Find the surface area of a regular prism iwth height 6 cm, if the base of the prism is: Equilateral triangle with a side of leng

th 3 cm and height of the triangle of aproximately 2.6 cm long.

1 answer:

ser-zykov [4K]2 years ago

4 0

Answer:

61.8 square centimeters

Step-by-step explanation:

You might be interested in

Solve for p. <br> P=?<br> 12 = p<br> 11 12

Mariulka [41]

Answer:

p = 144/11

Step-by-step explanation:

12/11 = p/12

~Simplify

12/11 = 1/12p

~Multiply 12 to both sides

144/11 = p

Best of Luck!

8 0

2 years ago

True or False: If your friend wants to take 6 hours for the 300 mile drive and you want to take 6 hours for the 240 mile drive,

Mila [183]

Answer: I'm pretty sure this is false.

Step-by-step explanation:

If you are driving the same amount of time as your friend, then you travel the same distance, unless you are going different speeds. The person that travels the most amount of distance would be going faster, in this case your friend.

Please don't quote me on this, I only THINK this is right, not 100%

4 0

2 years ago

Read 2 more answers

Each of the 90 fourth-grade students at North Elementary read 30 books over the school year.

kiruha [24]

Answer:

2700

Step-by-step explanation:

5 0

3 years ago

Write your question here (Keep it simple and clear to get the best answer) If jun has 12 T-shirt 6 pairs of parts, and 3 pairs o

Talja [164]

Answer:

the number of possibilities that can be drace himself up for the day is 216

Step-by-step explanation:

Given that

jun has 12 t-shirts,6 pairs of pants and 3 pairs of shoes

We need to find out the possibilities that can be drace himself up for the day

So here

$= 12C_1 \times 6C_1 \times 3C_1\\\\= \frac{12!}{1!(12 - 1)!} \times \frac{6!}{1!(6 - 1)!} \times \frac{3!}{1!(3 - 1)!}\\\\= \frac{12!}{1!(11)!} \times \frac{6!}{1!(5)!} \times \frac{3!}{1!(2)!}\\\\= 12 \times 6 \times 3\\\\= 216$

Hence, the number of possibilities that can be drace himself up for the day is 216

The same would be considered and relevant too

7 0

2 years ago

9. Given the point (6,-8) values of the six trig function.

lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10

$\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}$

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

$\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}$

3 0

2 years ago