1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ber [7]
3 years ago
6

Helpppppp!!!!!!!! pleaseee!!!!!!!!!!

Mathematics
1 answer:
vovangra [49]3 years ago
7 0

Adding all of the areas together:

5 x 6 = 30

4 x 6 = 24

3 x 6 = 18

4^2 + 3^2 = 16 + 9 = 25(square root) = 5

" " = 5

30 + 24 + 18 + 5 + 5 = 82 ft^2

You might be interested in
A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of
GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.989.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0
3 years ago
Divide 4 1/4 by 2. ​
Aleonysh [2.5K]
I’m pretty sure it’s 2 1/8
5 0
3 years ago
¿ cuáles son los adjetivos? y ¿ cuáles son los adjetivos ? por favor es para hoy <br>​
QveST [7]

Answer:

1) maldava y despota

2) pequenos

Step-by-step explanation:

4 0
3 years ago
What is the measure of DA? 15 90 105 165
seraphim [82]

Answer:

D. 165

Step-by-step explanation:

if A+n=180

75+90+n=180

165+n=180

n=180-165

n=15

A+n=180

A+15=180

A=180-15

A=165 (D)

3 0
2 years ago
Jonas wants to determine the enlarged dimensions of a photo to be framed. The original photo is 4 in. wide by 6 in. long. The ne
kenny6666 [7]

Answer:

15

Step-by-step explanation:

6 0
3 years ago
Other questions:
  • 2/3x-5=21<br> (2/3 is a fraction_
    14·2 answers
  • 3x+2y&gt;6 x-y&lt;1 graphing and shading
    5·1 answer
  • A machine that cost £35,000 is operated 8 hours a day in a 5-day week but one hour each day is used for test purposes. For use o
    14·2 answers
  • (Please help with these) (Im stuck on these)
    12·2 answers
  • What does x equal? Please help. No trolls
    7·1 answer
  • The science club raised money to clean the beach.They spent $29 on trash bags and $74 on waterproof boots.They still have $47 le
    10·1 answer
  • 3/5 of a number is 27, what us the number
    12·2 answers
  • Please help me! I will mark brainliest!
    6·2 answers
  • Question 4 (10 points)
    14·1 answer
  • The Hawks are starting a babysitting business. They charge an initial deposit of $25 and a rate of $4 an hour. A linear model is
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!