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Ber [7]
3 years ago
6

Helpppppp!!!!!!!! pleaseee!!!!!!!!!!

Mathematics
1 answer:
vovangra [49]3 years ago
7 0

Adding all of the areas together:

5 x 6 = 30

4 x 6 = 24

3 x 6 = 18

4^2 + 3^2 = 16 + 9 = 25(square root) = 5

" " = 5

30 + 24 + 18 + 5 + 5 = 82 ft^2

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Jacob wants to know the favorite sport among 6th grade students. Which types of survey below would give Jacob valid results?
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What is the length of the conjugate axis? (y-2)^2/16 -(x+1)^2/144=1
aleksandr82 [10.1K]

Answer: 24

A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.

the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.

The general equation for the vertical hyperbola is

            [ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1

The conjugate axis of the vertical hyperbola is y = k

Length of the conjugate axis  = 2b

According to the question k = 2, h = -1, a = 4, b = 12

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Learn more about hyperbola here :

brainly.com/question/3351710

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7 0
1 year ago
What is the length of AB?
Xelga [282]

Answer:

<em>AB = 7.35 cm</em>

Step-by-step explanation:

From the attachment,

In ΔDEF,

DF = GH-(GD+FH) = 6 - (2+3) = 1 cm

DE = 2+3 = 5 cm (sum of two radius)

Applying Pythagoras theorem,

EF=\sqrt{DE^2-DF^2}=\sqrt{5^2-1^2}=\sqrt{24}=2\sqrt6

In ΔCDI,

DI = GH-(GD+IH) = 6 - (2+1.5) = 2.5 cm

CD = 2+1.5 = 3.5 cm (sum of two radius)

Applying Pythagoras theorem,

CI=\sqrt{CD^2-DI^2}=\sqrt{3.5^2-2.5^2}=\sqrt6

AB = EF + CI = 2\sqrt6+\sqrt6=3\sqrt6=7.35\ cm

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