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2 years ago

Helpppppp!!!!!!!! pleaseee!!!!!!!!!!

Mathematics

1 answer:

vovangra [49]2 years ago

7 0

Adding all of the areas together:

5 x 6 = 30

4 x 6 = 24

3 x 6 = 18

4^2 + 3^2 = 16 + 9 = 25(square root) = 5

" " = 5

30 + 24 + 18 + 5 + 5 = 82 ft^2

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A grocer mixed pecans worth $0.84 per pound with cashews worth $1.40 per pound. If he made 88 pounds of a mixture worth $1.26 pe

Vsevolod [243]

Answer:

There are 22 pounds of pecans in the mixture

Step-by-step explanation:

Let the number of pounds of pecans be p and the number of cashews be c

We have 88 pounds in total, mathematically, this means;

c + p = 88

Now, the 88 mixtures cost $1.4 per pounds. This means the total amount of the 88 would be 88 * 1.26= $110.88

The pecans are worth 0.84 per pound while the cashews are worth 1.4 per pound. If the total is at a cost of 110.88, this can be translated mathematically as:

0.84p + 1.4c = 110.88

We now have two different equations that we can solve simultaneously.

c + p = 88

0.84p + 1.4c = 110.88

From the first equation, we can say c = 88 - p

We can then substitute the into the second equation:

0.84p + 1.4(88 - p) = 110.88

0.84p + 123.2 - 1.4p = 110.88

-0.56p = 110.88 - 123.2

0.56p = 12.32

p = 12.32/0.56 = 22

Now, we know c = 88 - p = 88 - 22 = 66

4 0

2 years ago

Read 2 more answers

The price of an item yesterday was $180. Today, the price rose to $279. Find the percentage increase.

olga55 [171]

Answer: 55%

1. 279 - 180 = 99

2. 99 divided by 180 = 0.55

3. 0.55 x 100 is 55.

55 is the percentage

3 0

3 years ago

Read 2 more answers

If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____

Sauron [17]

<h2>Answer:</h2>

$2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}$

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

$\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)$

So we need to find two things:

$2\vec{v}-6\vec{u}$

and:

$||2\vec{v}-6\vec{u}||$

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

$2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}$

SECOND:

If we name:

$\vec{w}=2\vec{v}-6\vec{u}$

Then, $||2\vec{v}-6\vec{u}||$ is the magnitude of the vector $\vec{w}$ . Therefore:

$||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}$