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Leno4ka [110]
3 years ago
14

From the graph below, find the total amount sold in 2005 and 2006.

Mathematics
2 answers:
alexira [117]3 years ago
6 0
B add subtract and find that is your answer

LenaWriter [7]3 years ago
6 0

Answer:

I would say c but I'm not sure

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Write the comparison below as a ratio in simplest form using a fraction, a colon, and the word to. 11 oz to 5 oz
adell [148]
Answer:

Explanation:

11 oz / 5 oz, 11 oz : 5 oz, eleven ounces to five ounces
8 0
3 years ago
Tickets sold for $3.50 and student tickets sold for $2.20 On a given night, 321 tickets were sold for $937.50. How many of each
k0ka [10]

Answer:

closest i got was 3.50(178) + 2.20(143)= $937.60

Step-by-step explanation:

7 0
3 years ago
Which expressions are equivalent to the one below? Check all that apply. 8^x
Dvinal [7]
\bf a)\qquad \left( \cfrac{32}{4} \right)^x\implies \left( \cfrac{8}{1} \right)^x\implies (8)^x\implies 8^x
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b)\qquad x^4\impliedby \textit{nothing to simplify}
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c)\qquad 8\cdot 8^{x-1}\implies 8^1\cdot 8^{x-1}\impliedby \textit{same base, add the exponents}
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\left. \qquad   \right.\left. \qquad   \right.8^{1+x-1}\implies 8^x

\bf d)\qquad \cfrac{32^x}{4}\implies \cfrac{(2^5)^x}{2^2}\implies (2^5)^x\cdot 2^{-2}\implies 2^{5x}\cdot 2^{-2}\implies 2^{5x-2}
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e)\qquad \cfrac{32^x}{4^x}\implies \left( \cfrac{32}{4} \right)^x\implies \left( \cfrac{8}{1} \right)^x\implies 8^x
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f)\qquad 8\cdot 8^{x+1}\implies 8^1\cdot 8^{x+1}\implies 8^{1+x+1}\implies 8^{x+2}
7 0
4 years ago
Please help me.........
Viktor [21]
Find the unit rate, which is also known as slope, constant rate of change!
8 0
3 years ago
This year, students in the 9th grade are collecting dimes and quarters for a school fundraiser. They are trying to collect more
BabaBlast [244]

Answer:

0.10d + 0.25q > 143.88

Step-by-step explanation:

Let the total dimes collected be d.

1\ dime = \$0.10

d\ dimes = \$0.10d

Let the total quarters collected be q.

1\ quarter = \$0.25

q\ quarters = \$0.25q

Last\ Year = \$143.88

Required

Represent as an inequality

The total collection, this year, can be represented as:

Total = 0.10d + 0.25q

From the question, we understand that:

This year's collections is expected to be greater than last year's

This can be represented as:

Total > Last\ Year

Substitute in the right values:

0.10d + 0.25q > 143.88

4 0
3 years ago
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