What is the volume of a rectangular prism with length 3 m, height 8 m, and width 12 m? A. 288 m2 B. 288 m3 C. 288 m

Help!!!!!!! please!!!! I will give brainliest, and 14 points!!!!! plz, no tiny links

sveticcg [70]

Answer:

21 1/3

Step-by-step explanation:

we turn the fraction into an improper fraction...

8/3 x 8/3 = (8*8)/3= 64/3 = 21 1/3

4 0

3 years ago

Read 2 more answers

Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall f

spin [16.1K]

Answer:

Part 1) 0.50 inches

Part 2) 1.14 inches

Part 3)

a) 1.25 inches

b) -0.32 inches

Step-by-step explanation:

The complete question in the attached figure

Part 1) Last June only 0.17 inches of rain fell all month. What is the difference between the average rainfall and the actual rainfall for the last June

Let

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

The difference between the average rainfall and the actual rainfall for the last June is given by the expression

$(x-y)$

we have

$x=0.67\ in\\y=0.17\ in$

substitute

$0.67-0.17=0.50\ in$

Part 2) The departure from the average rainfall last July was -0.36 inches. How much rain fell last July?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

$D=y-x$

we have

$D=-0.36\ in\\x=1.5\ in$

substitute the given values

$-0.36=y-1.5$

solve for y

$y=1.5-0.36\\y=1.14\ in$

Part 3)

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Part b) What would the departure from the average be in August in that

situation?

Part a) How much rain would have to fall in August so that the total amount of rain equals the average rainfall for these three months?

Find the average rainfall for these three months

Adds the average rainfall and divide by 3

$(0.67+1.5+1.57)/3=1.25\ in$

Part b) What would the departure from the average be in August in that

situation?

we know that

The departure from the average is the difference between the actual amount of rain and the average amount of rain for a given month

Let

D -----> the departure from the average

x ----> the average rainfall for the last June

y ----> the actual rainfall for the last June

so

$D=y-x$

we have

$x=1.57\ in\\y=1.25\ in$

substitute the given values

$D=1.25-1.57=-0.32\ in$

7 0

4 years ago

(x + 7) + (y + 4)2 = 16 Center: Radius:

tigry1 [53]

Answer:

Center: (-7, -4)

radius = 4

Explanation:

Equation: (x + 7)² + (y + 4)² = 16

Circle formula:

(x - h)² + (y - k)² = r²

(h, k) denotes the center of the circle, "r is radius"

Rewrite the following equation in standard form:

(x - (-7))² + (y - (-4))² = 4²

From this identify:

h = -7, k = -4, radius = 4

6 0

2 years ago

Read 2 more answers

The length of a rectangle is 7 inches longer than it is wide. If the area is 44 square inches, what are the dimensions of the re

MatroZZZ [7]

Area = *Longer Side* x *Shorter side*

44 = (x + 7) * x
44 = x^2 + 7x
0 = x^2 + 7x - 44
0 = (x + 11)(x - 4)
0 = x + 11 OR 0 = x - 4
x = -11*impossible* OR x = 4
So x = 4

8 0

3 years ago

Solve the inequality. -8y_<40 The solution is .

emmasim [6.3K]

Answer:

Hi! The answer to your question is y $\geq$ -5

Step-by-step explanation:

☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆

☁Brainliest is greatly appreciated!☁

Hope this helps!!

- Brooklynn Deka

5 0

3 years ago