The intercepts are 5x+3y=30 how do you graph the linear equation ?

Mathematics

2 answers:

Vlad1618 [11]4 years ago

6 0

Use y=mx+b
<span>y=-5/3x+10 </span>

Andrej [43]4 years ago

4 0

You would have to find the x and y intercepts.

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Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side

svp [43]

A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6

Last, we have all the information needed in order to calculate the area by the formula:

$A = \frac{(AB + CD)DH}{2}$

A = (7 + 5) × 2√6 ÷ 2
= 12√6

The area of the regular trapezoid is 12√6 square units.