Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side
sides are 5.
1 answer:
A regular trapezoid is shown in the picture attached.
We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5
Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:
AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1
Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6
Last, we have all the information needed in order to calculate the area by the formula:
A = (7 + 5) × 2√6 ÷ 2
= 12√6
The area of the regular trapezoid is 12√6 square units.
We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5
Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:
AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1
Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6
Last, we have all the information needed in order to calculate the area by the formula:
A = (7 + 5) × 2√6 ÷ 2
= 12√6
The area of the regular trapezoid is 12√6 square units.
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Area of rectangle = 2(2w - 5) is the factored form of given expression
Multiplying the length and width of a rectangle, we get the area of the rectangle
<em><u>Solution:</u></em>
Given that, area of rectangle is 4w - 10 square units
We have to factor the expression
From given,
Area of rectangle = 4w - 10
Take 2 as common factor
Area of rectangle = 2(2w - 5)
Thus the given expression is factored
<em><u>The area of rectangle is given as:</u></em>
Thus, multiplying the length and width of a rectangle, we get the area of the rectangle
When we multiply 2 with 2w - 5 we get the area of rectangle
From above we can say,
Length = 2 or 2w - 5
Width = 2w - 5 or 2
So when dimensions of rectangle are multiplied we get area of rectangle