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agasfer [191]
3 years ago
5

Find the number of ways of arranging the numbers 1,2,3,4,5,6,7, if no two even numbers can be adjacent, and no two odd numbers c

an be adjacent.
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

24 ways

Step-by-step explanation:

1) In Combinatorics when we arrange a number and the order matter, we call it arrange the possibilities. For this exercise let's not use formulas but reasoning.

2) For this case we need a two figure number. Since we have seven numbers.

Since there is no repetition, all the possibilities are:

7*6=42

3) But there is a restriction it's forbidden adjacent even and odd numbers: These numbers we don't want them:

13 15 17

24 26

31 35 37

42 46

51 53 57

62 66

71 73 75

<u>18 non desirable results</u>

The total arrangements minus the not possible combinations, will match the possible results:

42-18=24

3) Just for checking, we have here the allowed combinations:

12 14 16

21 23 25 27

32 34 36

41 43 45 47

52 54 56

61 63 65 67

72 74 76  

A total of 24 possible ways.

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