Answer:
c. 48 packages
d. Possibilities:
1 x 28 = 28
2 x 14 = 28
4 x 7 = 28
7 x 4 = 28
14 x 2 = 28
28 x 1 = 28
Possible combinations:
17, 1, 28
17, 2, 14
17, 4, 7
17, 7, 4
17, 14, 2
17, 28, 1
Step-by-step explanation:
c. 127 employees get 3 uniforms each, meaning a total of 127 * 3 = 381 uniforms
The uniforms come in packs of 8, so dividing 381 by 8, we get:
381/8 = 47.625
However, you probably can't order a portion of a package, so you must round up to 48 packages. There will be 3 uniforms left over.
d. The divisors of 28 are 1, 2, 4, 7, 14, and 28. All I did was enumerate the six possibilities.
Answer:
d
Step-by-step explanation:
2x+3x-9-1
x
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The nth term of an AP = a + (n - 1)d
The pth term of the AP = a +(p - 1)d = 1/q
The qth term of the AP = a +(q - 1)d = 1/p
Sum of nth term = (n/2)(2a + (n - 1)d)
Sum for 20th term = (20/2)(2a + (20- 1)d) = 10(2a + 19d)
a +(p - 1)d = 1/q .....(a)
a +(q - 1)d = 1/p ......(b)
Equation (a) - (b)
a - a + (p - 1)d - (q - 1)d = 1/q - 1/p
pd - d -qd + d = (p - q)/pq
pd - qd = (p - q)/pq
(p - q)d = (p - q)/pq
Cancel out (p - q) from both sides
d = 1/(pq)
Recall a +(p - 1)d = 1/q .....(a)
a +(p - 1)(1/pq)= 1/q
a + (p - 1)/(pq) = 1/q
a = (1/q) - (p - 1)/(pq)
a = (p - (p - 1))/(pq)
a = (p - p + 1) / (pq)
a = 1/(pq)
a = 1/(pq), d = 1/(pq)
Recall sum of 20 terms:
10(2a + 19d)
10(2*(1/(pq)) + 19*(1/(pq)))
10 ( 2/(pq) + 19/(pq)) = 10* (2 + 19)/(pq)
= 10*21/(pq)
= 210 / (pq)
Sum of the 20 terms = 210/(pq)
Hope this explains it.
Answer:
8pi
Step-by-step explanation:
hmu for an explanation
Answer:
Arithmetic
Step-by-step explanation:
Since arithmetic means adding or subtracting a common difference, we see the differences in each term. We notices the differences is 3, so the common difference is 3.