Answer:
9/2 if n goes to infinity and that the 2n^3 is under the whole expression
Step-by-step explanation:
Let me clear this .
find limit (9n^3 + 5*n - 2)/ (2n^3)
as n --> infinity
Did I put the parentheses in the right spot?
because if you leave it the way you did, then the whole expression goes to positive infinity as n goes to infinity But I will do this with parentheses
so
find limit (9n^3 + 5*n - 2)/ (2n^3)
simplify expression
limit (9/2) + 5/(2n^2) - 1/(n^3)
= (9/2) + 0 - 0
= (9/2)
Answer:
p-q= -4
p=q-4
x^2 + px + q=0
=> x^2 + (q-4)x + q = 0
d= b^2-4ac
=(q-4)^2 - 4(1)(q)
= q^2 + 16 -8q - 4q
=q^2 -12q+16
given that D=16
q^2 -12q+16 = 16
=> q^2 -12q = 0
=> q^2 = 12q
=> q = 12q/q
=> q= 12
Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8
Hope you understood............
Answer:
12
Step-by-step explanation:
Distribute the negative which would get your 3x + 6 -3x + 6. The 3x would cancel out and you would add 6+6 = 12
I say 12 because that would mean the first rectangle is 6x12 and the second is 10x12
The range is (10,11.5,12.5,13.75)
Enjoy your day, mi amor! ❤️
