Question

(2k^3-7k^2+3k) -(-4k^2+5k)=(2k 3 −7k 2 +3k)−(−4k 2 +5k)=

Answer 1

Answer:

k = 1

 k = 0

Step-by-step explanation:

Equation at the end of step  1  :

((((2•(k3))-(7•(k2)))+3k)-((0-(4•(k2)))+5k))-((((2•(k3))-7k)+3k)-((0-22k2)+5k)) = 0

Step  2  :

Equation at the end of step  2  :

((((2•(k3))-(7•(k2)))+3k)-((0-(4•(k2)))+5k))-(((2k3-7k)+3k)-(5k-4k2)) = 0

Step  3  :

Equation at the end of step  3  :

((((2•(k3))-(7•(k2)))+3k)-((0-22k2)+5k))-(2k3+4k2-9k) = 0

Step  4  :

Equation at the end of step  4  :

((((2•(k3))-7k2)+3k)-(5k-4k2))-(2k3+4k2-9k) = 0

Step  5  :

Equation at the end of step  5  :

(((2k3 - 7k2) + 3k) - (5k - 4k2)) - (2k3 + 4k2 - 9k) = 0

Pulling out like terms :

 7.1     Pull out like factors :

   7k - 7k2  =   -7k • (k - 1) 

Equation at the end of step  7  :

-7k • (k - 1) = 0