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2 years ago

If the cost per book is 6.5. How much would 5 books cost?

Mathematics

2 answers:

____ [38]2 years ago

8 0

To get this answer, you multiply 6.5 and 5. The answer is 32.5

Sindrei [870]2 years ago

4 0

Write the first 4 terms of the sequence defined by the rule f (n= n + 10

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What value can be written on the blank line to make the expressions equivalent?

KIM [24]

Hello!

I believe the number that can be written in the blank space above is 6.

48+54=6'(8+9)

The number written in the blank space is 6 because when you divide 48 and 54 by their numbers, 8 and 9, you will get an answer of 6 for both numbers.

48/8=6
54/9=6

So the number in the blank space would be 6.

I hope this helps!

3 0

3 years ago

Read 2 more answers

Find the maximum rate of change of f(x,y,z=x y/z at the point (2, -3, 5 and the direction in which it occurs. maximum rate of ch

kherson [118]

$f(x,y,z)=x+\dfrac yz$
$\implies \nabla f(x,y,z)=\left(1,\dfrac1z,-\dfrac y{z^2}\right)$
$\implies \nabla f(2,-3,5)=\left(1,\dfrac15,\dfrac3{25}\right)$

The maximum rate of change is then

$\|\nabla f(2,-3,5)\|=\dfrac{\sqrt{659}}{25}$

which occurs in the direction of $\nabla f(2,-3,5)$ above.

6 0

3 years ago

A jar contains 2 orange balls, 5 black balls, and 3 pink balls.

Levart [38]

The probability of Event A is 5/10 which simplifies to 1/2.

The probability of Event B is 3/9 which simplifies to 1/3.

Because it says "and" we need to multiply them which gives us 1/2*1/3=1/6

7 0

3 years ago

Read 2 more answers

Q3 make c the subject

Lorico [155]

Answer:

c=(ay-2)/m

Step-by-step explanation:

Isolate c

First I would multiply both sides by y

mc+2=ay

Then I would subtract 2

mc=ay-2

Then I can divide my m to get c alone

c=(ay-2)/m

5 0

2 years ago

Intergal of 8sin^4(x)dx

Romashka-Z-Leto [24]

$\int\limits8sin^4(x)dx =$

Take the constant out $\int\limits a*f(x)dx=a* \int\limitsf(x)dx$

$= 8 \int\limits sin^4(x)dx$

$\int\limits sin^4(x)dx = - \frac{cos(x)sin^3(x)}{4} = \frac{3}{4} \int\limits sin^2(x)dx$

$= 8( -\frac{cos(x)sin^3(x)}{4}+ \frac{3}{4} \int\limits sin^2(x)dx)
$

Use the following identify : $sin^2(x) = \frac{1-cos(2x)}{2}$

$= 8(- \frac{cos(x)sin^3(x)}{4} + \frac{3}{4} \frac{1}{2}( \int\limits 1 - cos(2x)dx)$

$\int\limits 1dx = x$

$\int\limits cos(2x)dx = \frac{1}{2} sin(2x)$

Apply the sum rule :

$=8(- \frac{cos(x)sin^3(x)}{4} + \frac{3}{4} \frac{1}{2} (x- \frac{1}{2} sin(2x))$

Simplify :

$8( \frac{3}{8} (x- \frac{1}{2} sin(2x)) - \frac{1}{4} sin^3(x)cos(x))$

Therefore add a constant to the solution:

$= 8 ( \frac{3}{8} (x- \frac{1}{2} sin(2x)) - \frac{1}{4} sin^3(x)cos(x))+C$

hope this helps!

3 0

2 years ago