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AveGali [126]
3 years ago
10

un triángulo tiene un área de 648 metros cuadrados si la base es el triple de la altura Cuáles son las dimensiones o medidas de

dicho triángulo buscando su modelo matemático sus datos su fórmula su desarrollo algebraico y su resultado ​
Mathematics
1 answer:
slava [35]3 years ago
3 0

Answer:

base ≈ 62.354 m

altura ≈ 20.785 m

Step-by-step explanation:

area de triangulo formula= 1/2(base)(altura)

1/2 (3x)(x)=648

(3x)(x)=3x²

1/2(3x²)=648

648÷1/2=1296

3x²=1296

x²=432

x≈20.785

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3 years ago
HELP <3 Match the expressions with their solutions.
densk [106]

Answer:

1 ) sin 165°

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4 ) sin^2 157.5

Step-by-step explanation:

1 )

Given expression is  \sqrt{\frac{1-cos330}{2} }

We know that cos2x=1-2sinx^{2}

sinx^{2}=\frac{1-cos2x}{2}

(sinx/2)^2=\frac{1-cosx}{2}

So the first expression is sin (330/2)° =sin 165°

2 )

GIven expression is  1-2sin^2165

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So the result is cos 330°

3 )

Given expression is \frac{1-cos 315}{sin315}

We know that cos2x=1-2sinx^{2}

Also we know that sin2x = 2sinxcosx

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So the result is Tan 157.5°

4 )

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We know that cos2x=1-2sinx^{2}

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6 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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3 years ago
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2 years ago
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