FP!!!!!!!!!!!!! :) (5 x 3) + 5 =
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Calculate the hypotenuse( h ) using Pythagoras' identity
h =√(4² + 7²) = √(16 + 49) = √65
sinΘ = 4 / √65 ⇒ cscθ = √65 / 4
cosθ = 7/ √65 ⇒ secθ = √65 / 7
tanθ = ⇒ cotθ =
Calculate the hypotenuse( h ) using Pythagoras' identity
h =√(4² + 7²) = √(16 + 49) = √65
sinΘ = 4 / √65 ⇒ cscθ = √65 / 4
cosθ = 7/ √65 ⇒ secθ = √65 / 7
tanθ = ⇒ cotθ =