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aivan3 [116]
3 years ago
14

Write the decimal as a fraction or mixed number in simplest form. 5.22​

Mathematics
2 answers:
fredd [130]3 years ago
8 0

Answer:

5 11/50

Step-by-step explanation:

i used an online calculator and thats what it said

Bingel [31]3 years ago
7 0

Answer:

5 2/9

Step-by-step explanation:

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Can someone help me with this please?!?!?!?
dusya [7]
Answer

17 m^3

Explanation

Volume of a given prism = bh

Where b = base area and h = height of prism

Base area = 1 • 2/2 (b • h /2)

= 1

Height = 17

17 • 1 = 17 m^3
5 0
3 years ago
Find the value of x and y​
notsponge [240]

Answer:

z

Step-by-step explanation:

z

6 0
3 years ago
Could anybody help me (pic attached)​
RideAnS [48]

Answer: 4/3

Step-by-step explanation:

What are the corresponding sides?

4 and 3

8 and 6

9 and 6.75

This is very easy, just make a fraction

4/3 = 4/3

8/6 = 4/3

9/6.75 = 4/3

Hence the answer is 4/3

5 0
3 years ago
Tabitha and her mother went to the pet store. Her mother told her she could either choose a cat, dog, or fish, and either get a
FinnZ [79.3K]
For the pet the fraction is 2/3 because there is a fish,cat and a dog only cats and dogs have 4 legs and the fraction for the toy or the book is 1/2 because there are 2 objects and she can only get 1
7 0
3 years ago
The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 oun
Ugo [173]

Answer: A) .1587

Step-by-step explanation:

Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.

i.e. \mu=12.30 and \sigma=0.20

Let x denotes the amount of soda in any can.

Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.

Then, the probability that a randomly selected can will need to go through the mentioned process =  probability that a randomly selected can has more than 12.50 ounces of soda poured into it =

P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587

Hence, the required probability= A) 0.1587

6 0
3 years ago
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