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2 years ago

Write a word problem that can be solve using an

Mathematics

2 answers:

DanielleElmas [232]2 years ago

7 0

Step-by-step explanation:Write a word problem that can be solve using an

equation of the form ax + b = c.

Include at least one decimal or fraction.

please help it’s due soon I need to do

aleksley [76]2 years ago

3 0

Answer:

A swimming pool charges an entrance fee of $2 per person plus $0.25 for each 10 minutes they spend in the pool. How much did it cost for Katy to swim for 90 minutes?

let y = total cost

let x = number of 10 minute periods spent in pool

⇒ y = 0.25x + 2

If Katy spent 90 minutes in the pool, x = 9:

⇒ y = 0.25 x 9 + 2 = 4.25

So it cost Katy $4.25 to swim for 90 minutes.

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x^3-10x^2-27x-18=0 also has three solutions

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2 years ago

In Roman Numerals, a bar means to multiply that number by 1000. What is 99 004 in roman numerals?

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2 years ago

I need help on this please anyone help

joja [24]

x + 90 = 7x

90 = 7x - x

90 = 6x

x = 90/6

x = 15

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11 months ago

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Klio2033 [76]

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10 months ago

Which are the side lengths of a right triangle? Check all that apply.

BaLLatris [955]

Answer:

3, 14, and StartRoot 205 EndRoot

19, 180, and 181

2, 9, and StartRoot 85 EndRoot

Step-by-step explanation:

we know that

In a right triangle, the length sides must satisfy the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the greater side (the hypotenuse)

a and b are the legs

Part 1) we have

3, 14, and StartRoot 205 EndRoot

we have

$c=\sqrt{205}\ units$

$a=3\ units\\b=14\ units$

substitute

$(\sqrt{205})^2=3^2+14^2$

$205=205$ ----> is true

Satisfy the Pythagorean theorem

therefore

These are the lengths of a right triangle

Part 2) we have

6, 11, and StartRoot 158 EndRoot

we have

$c=\sqrt{158}\ units$

$a=6\ units\\b=11\ units$

substitute

$(\sqrt{158})^2=6^2+11^2$

$158=157$ ----> is not true

Not satisfy the Pythagorean theorem

therefore

These are not the lengths of a right triangle

Part 3) we have

19, 180, and 181

we have

$c=181\ units$

$a=19\ units\\b=180\ units$

substitute

$181^2=19^2+180^2$

$32,761=32,761$ ----> is true

Satisfy the Pythagorean theorem

therefore

These are the lengths of a right triangle

Part 4) we have

3, 19, and StartRoot 380 EndRoot

we have

$c=\sqrt{380}\ units$

$a=3\ units\\b=19\ units$

substitute

$(\sqrt{380})^2=3^2+19^2$

$380=370$ ----> is not true

Not satisfy the Pythagorean theorem

therefore

These are not the lengths of a right triangle

Part 5) we have

2, 9, and StartRoot 85 EndRoot

we have

$c=\sqrt{85}\ units$

$a=2\ units\\b=9\ units$

substitute

$(\sqrt{85})^2=2^2+9^2$

$85=85$ ----> is true

Satisfy the Pythagorean theorem

therefore

These are the lengths of a right triangle

5 0

3 years ago

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