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erastova [34]
2 years ago
9

Hallie bikes 1 5/8 km before lunch 6 1/4 km How much farther does hallies bike after lunch than before lunch? Express your answe

r as a mixed number in simplest form. Enter your answer in the box.
Mathematics
1 answer:
kodGreya [7K]2 years ago
8 0

Distance covered by Hallie before lunch= 1 5/8 km.

Converting it into imperoper fractions we get (1*8+5)/8= 13/8 km.

Distance covered by Hallie after lunch = 6 1/4 km.

Converting it into imperoper fractions we get (6*4+1)/4 = 25/4 km.

Difference between distances = Distance covered after lunch - Distance covered before lunch.

=25/4 km - 13/8 km

Subtracting fractions by taking common denominator, we get

25/4 - 13/8  = 50/8 - 13/8 = 37/8

Let us convert 37/8 into mixed fraction now.

On dividing 37 by 8, we get quotient 4, and 5 remainder.

So, 37/8 = 4 5/8.

Therefore, Hallie bikes 4 5/8 km farther after lunch than before lunch.


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The following list details the numbers of tickets sold for a talent show grade 9:22; grade 10:32; grade 11: 41; and grade 12:30.
Montano1993 [528]

Answer: C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)

Step-by-step explanation:

The data set is:

(9, 22)

(10,32)

(11, 41)

(12, 30).

In the usual notation, the number at the left is the input (belons to the domain) and the number in the right is the output (belongs to the range).

Then the domain would be:

{9, 10, 11, 12}

and the range:

{22, 32, 41, 30}

The correct option is C

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2 years ago
If area of a square is 121 cm2 what is side length
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The answer is 30.25 or as a fraction 30 1/4
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3 years ago
If x^2 = 30, what is the value of x?
Lapatulllka [165]
x= +\sqrt{30} ~or ~ -\sqrt{30}
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5 0
2 years ago
4, 02, 03, α4, 28.<br> Find the common difference
hram777 [196]

Answer:

1

Step-by-step explanation:

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5 0
3 years ago
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
2 years ago
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