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Rama09 [41]
2 years ago
9

in the diagram, AE is tangent to the circle at point a and secant DE intersects the circle at point C and D. the iines intersect

outside of the circle at point E
Mathematics
1 answer:
AlexFokin [52]2 years ago
8 0
Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10

I suspect a typo somewhere in the murk above
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Is y=x^2+7 a linear equation?
tankabanditka [31]

Answer:

No, it is not a linear equation

Step-by-step explanation:

This equation contains the term x², meaning that it is a quadratic function (parabola)

So, it is not a linear equation.

If it were a linear equation, x would not be squared, and the equation would have been in y = mx + b form.

The answer is no, it is not a linear equation.

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Choose all the quadratic pairs that are equivalent. 1 2 (x + 4)2 = 2 x2 + 8x + 15 = 0 (x − 5)2 = 1 x2 − 10x + 26 = 0 3(x − 1)2 +
Artemon [7]

Answer:

Only equation 1 and 2 are equal.

Step-by-step explanation:

2 (x + 4)2 = 2

2( x² + 8x+ 16) = 2               Applying the square formula

2x² + 16x+ 32 = 2

2x² + 16x+ 32 -2= 0

2x² + 16x+ 30 = 0

2( x² + 8x+ 15)= 0           Taking 2 as common

x2 + 8x + 15 = 0------------eq 1

x2 + 8x + 15 = 0-------------eq 2

(x − 5)2 = 1

x²-10x+25= 1             Applying the square formula

x²-10x+25- 1= 0

x²-10x+24= 0-------------eq 3

x2 − 10x + 26 = 0 -------------eq 4

3(x − 1)2 + 5 = 0

3( x²-2x+1)+5= 0               Applying the square formula

3x²-6x+3+5= 0

3x²-6x+ 8= 0-------------eq 5

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3 0
3 years ago
(8x+5)+(4x-3) what is that equal to
Anna [14]

Answer:

12x + 2

Step-by-step explanation:

To find what the expression equals, you can collect like terms. This means to do the operations (add or subtract) the numbers that have the same variables.

(8x + 5) + (4x - 3)        Remove brackets to add a binomial (2-term brackets)

= 8x + 5 + 4x - 3        Collect like terms

= 8x + 4x + 5 - 3        I rearranged so you can see which terms are alike

= 12x + 5 - 3        Collected like terms with "x" (8x + 4x = 12x)

= 12x + 2        Collected like terms with no variables (5 - 3 = 2)

Therefore (8x + 5) + (4x - 3) is equal to 12x + 2.

If you want, you can also find another equal expression by factoring. Since "12x" and "2" are both divisible by the factor 2, you can <em>take it out</em> and put the other numbers in a bracket.

12x + 2

= 2(12x/2 + 2/2)

= 2(6x + 1)        This is equal, but in factored form.

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