n=9
Step-by-step explanation:
6^10 = 60466176
6^-4 0.00077160493
60466176 x 0.00077160493 = 46655.9994998
, which is the numerator
6^-5 = 0.00012860082
6^2 = 36
0.00012860082 x 36 = 0.00462962952
46655.9994998 / 0.00462962952 = 10077696
6^9 = 10077696
Therefore, n=9
Answer:
D. 39°
Step-by-step explanation:
mAB = (3x + 9°)
mCD = (11x – 71)
From the diagram: |AB|=|CD|
Since arcs AB and CD are subtended by a chord of equal length.
mAB=mCD
3x + 9°=11x – 71°
Collect like terms to solve for x
11x-3x=9°+71°
8x=80°
x=10°
Therefore, the measure of AB:
mAB = (3x + 9°)
=3(10)+9
=30+9
=39°
The correct option is D.
<h2>
Hello!</h2>
The correct option is:
C.
<h2>
Why?</h2>
To find which of the given options are not the result of a substitution in the given system, we need to isolate the variable in function of the other variable, and then substitute it.
So, substituting and discarding, we have:
- First equation:
Isolating "y", we have:
Then, substituting it into the second equation, we have:
We have that it's a result of a substitutiong in the following system (option A)
- Second equation:
Isolating "y", we have:
Then, substituting it into the first equation, we have:
Have a nice day!
You can make $0.49 but using 1 quarter 1 dime 2 nickels and 4 pennies.
The answer to the above equation is 3
Step-by-step explanation:
(a-b)³+(b-c)³+(c-a)³: (a-b)(b-c)(c-a)
Let us consider (a−b)= x, (b−c)= y and (c−a)= z.
Hence, It is obvious that:
x+y+z =0 ∵all the terms gets cancelled out
⇒We must remember the algebraic formula
x³+y³+z³−3xyz= (x+y+z) (x²+y²+z²-xy-xz-yz)
Since x+y+z=0 ⇒Whole “(x+y+z) (x²+y²+z²-xy-xz-yz)
” term becomes 0
x³+y³+z³−3xyz =0
Alternatively, x³+y³+z³= 3xyz
Now putting the value of x, y, z in the original equation
(a-b)³+(b-c)³+(c-a)³ can be written as 3(a-b)(b-c)(c-a) since (a−b)= x, (b−c)= y and (c−a)= z.
3(a-b)(b-c)(c-a): (a-b)(b-c)(c-a)
= 3 ∵Common factor (a-b)(b-c)(c-a) gets cancelled out
Answer to the above question is 3