Does anybody know how to do this? Problem 13

Mathematics

1 answer:

inessss [21]3 years ago

4 0

Subtract 6 from the x value in the first one, and remember that slope intercept form is mx+b

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Find the domain of the function f (x) = 2/x-4 + 1/x+2

Andreas93 [3]

As written, the denominator in both fractions is x, so the only restriction on the domain is ... x ≠ 0.

_____

We suspect you intend ...

... f(x) = 2/(x-4) +1/(x+2)

which is undefined when x = 4 or x = -2.

The domain is all real numbers except -2 and 4.

6 0

3 years ago

Given that WA = 5x – 8 and WC = 3x + 2, find WB. A. WB = 5 B. WB = 8 C. WB = 10 D. WB = 17

rodikova [14]

The rest of the question is the attached figure.
============================================
Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
And AY = YB ⇒⇒⇒ ∴ WA² = YB² + YW² → (1)
Δ BYW a right triangle at Y ⇒⇒⇒ ∴ WB² = BY² + YW² → (2)
From (1) , (2) ⇒⇒⇒ ∴ WA = WB →→ (3)
Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
And CX = XB ⇒⇒⇒ ∴ WC² = XB² + XW² → (4)
Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW² → (5)
From (4) , (5) ⇒⇒⇒ ∴ WC = WB →→ (6)
From (3) , (6)
WA = WB = WC
given ⇒⇒⇒ WA = 5x – 8 and WC = 3x + 2
∴ <span> 5x – 8 = 3x + 2</span>
Solve for x ⇒⇒⇒ ∴ x = 5
∴ WB = WA = WC = 3*5 + 2 = 17

The correct answer is option D. WB = 17