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3 years ago

(y+3) (y^2-3y+9) What is the product? y3 + 27 y3 – 27 y3 – 6y2 + 27 y3 + 6y2 + 27

Mathematics

2 answers:

Mashutka [201]3 years ago

5 0

A is the answer hope this helps

nata0808 [166]3 years ago

5 0

The correct answer is: [A]: " y³ + 27 " .
____________________________________
Explanation:
____________________________________
(y + 3) (y² − 3y + 9) =

y*y² = y³

-3y *y = − 3y²

+9*y = + 9y
__________________
= (y³ − 3y² + 9y) ;
____________________________
+3*y² = + 3y²

-9*y = − 9y

(+3)*(+9) = + 27
____________________________
= (3y² − 9y + 27) ;
____________________________

→   (y + 3) (y² − 3y + 9) =
______________________________________
      (y³ − 3y² + 9y) + (3y² − 9y + 27) =
______________________________________
         y³ − 3y² + 9y + 3y² − 9y + 27 = ?
_____________________________________
Combine the "like terms":
_____________________________________
y³ ;

− 3y² + 3y² = 0 ; [cancel out] ;

+ 9y − 9y = 0 ; [cancel out] ;

+ 27 ;
__________________________________________
to get:
__________________________________________
    " y³ + 27 " ;
__________________________________________
→ which is: Answer choice [A]: " y³ + 27 " .
__________________________________________

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