Question

(y+3) (y^2-3y+9) What is the product? y3 + 27 y3 – 27 y3 – 6y2 + 27 y3 + 6y2 + 27

Answer 1

 A is the answer hope this helps

Answer 2

The correct answer is:  [A]:  " y³ + 27 " .
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Explanation:
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 (y + 3) (y² − 3y + 9) =

y*y²  = y³

-3y *y  =  − 3y²
 
+9*y = + 9y
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  =  (y³  −  3y²  +  9y) ;
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+3*y² =  + 3y²

-9*y =  − 9y

(+3)*(+9) =  + 27
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  =  (3y²  −  9y  +  27) ;
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→   (y + 3) (y² − 3y + 9) = 
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      (y³  −  3y²  +  9y)  +  (3y²  −  9y  +  27)  =
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         y³  −  3y²  +  9y  +  3y²  −  9y  +  27  = ?
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Combine the "like terms":
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y³ ;

− 3y² + 3y² = 0 ; [cancel out] ; 

+ 9y − 9y = 0 ; [cancel out] ;

+ 27 ;
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to get:
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    " y³ + 27 " ;
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  →  which is:  Answer choice  [A]:  " y³ + 27 " .
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