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Citrus2011 [14]
3 years ago
7

Place parentheses in each equation, if needed, to make each equation true. WILL GIVE BRAINLIEST AND FRIEND YOU. PLEASE ANSWER VE

RY EASY
A. 7 + 3 x 2 + 4 = 25

B. 8 to the second power divided by four times eight equals two

C. 16+8-5x2=14
Mathematics
1 answer:
bezimeni [28]3 years ago
3 0
A. 7 + 3 x (2 + 4) = 25
7 + 3 x 6 = 25
7 + 18 = 25
25 = 25
B. 8^2 divided by 4 x 8 = 2
64 divided by 4 x 8 = 2
64/32 = 2
2 = 2
C. (16 + 8) - 5 x 2 = 14
24 - 5 x 2 = 14
24 - 10 = 14
14 = 14
For each problem use the basis of the acronym PEMDAS.
P arentheses (grouping symbols)
E xponents
M ultiplication
D ivision
A ddition
S ubtraction

Evaluate each step in that order.
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Factor the trinomial:<br> 2x^2+13x+21
svet-max [94.6K]

Answer:

(2x + 7)(x + 3)

Step-by-step explanation:

2x² + 13x + 21

2x² + 6x + 7x + 21

2x(x + 3) +7(x + 3)

(2x + 7)(x + 3)

3 0
3 years ago
An oil drilling company is drilling a hole. The elevation of the bottom of the hole changes by feet each day. After a certain nu
marin [14]

Answer:

option.D

Step-by-step explanation:

  • each day it changes by -73\frac{1}{4}
  • so for two days , the elevation becomes  -73\frac{1}{4} +  -73\frac{1}{4}
  • for 3 days :  -73\frac{1}{4} +  -73\frac{1}{4} +  -73\frac{1}{4}
  • so, for n days,  -73\frac{1}{4} + ........ n times

=  n*-73\frac{1}{4}

  • therefore, for x days, elevation = x*-73\frac{1}{4}
  • as it is given that after certain days this elevation has reached -366\frac{1}{4}
  • so, x*-73\frac{1}{4} = -366\frac{1}{4}
3 0
3 years ago
Use the following frequency distribution (of SAMPLE DATA) in answering the questions: class 0-9 f=10; class 10-19 f=20; class 20
lutik1710 [3]

Answer:

1. Five classes in the frequency distribution

2.The mid point of the third class is 24.5

3.The total number of frequency is 100

4.The relative frequency of the third class is (20/100=0.2)

5. We use n-1 because we are dealing with a sample data

6. The mean is 24.5

7. The value of the standard deviation is 11

Step-by-step explanation:

See attached picture for the solutions

4 0
3 years ago
Find an equation that models the path of a satellite if its path is a hyperbola, a = 55,000 km, and c= 81,000 km. Assume the cen
elena-14-01-66 [18.8K]

Answer:

\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1

Step-by-step explanation:

the transverse axis is horizontal.

so its a horizontal hyperbola

Center is the origin so center is (0,0)

Equation of horizontal hyperbola is

\frac{x^2}{a^2} - \frac{y^2}{b^2} =1

Given a= 55000 and c= 81000

c^2 = a^2 + b^2

81000^2 = 55000^2 + b^2

subtract 55000^2 on both sides

b  = sqrt(81000^2 - 55000^2)= 59464.27

now plug in the values

\frac{x^2}{55000^2} - \frac{y^2}{59464^2} =1

7 0
3 years ago
Janelle has $75. She buys jeans that are on sale for half price and then uses an in-store coupon for $10 off. After paying $1.80
kramer
75.00-37.20=37.80-1.80=36.00
so she spent 36.00 with sales tax . then 36.00*2=72.00+10.00=82.00
the jeans original price was 82.00 
 Check:
6 0
3 years ago
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